sending array to PHP via $.post issue

Question

I have an issue when sending to server array in POST via ajax with JQuery version is 1.10.2. My array is array of objects (such object is basically an associative array).

Function JSON.stringify(word_mean_arr); return [[]] - so it fail to work and if I simply write:

$.post( "./ajax2/myscript.php", {block_id: bl_id, wm_arr: word_mean_arr})

I cannot get value of $POST['wm_arr'] like it does not exist.

Example of my array is something like:

[[key]=>1,[value]=>"this_is_"],[[key]=>2,[value]=>"this_is_str2"]

So my object is:

[  [key]=>1,   [value]=>"this_is_str"]

This is how I form my array

var word_mean_arr = new Array();
for (var i = 0; i <= this.n_of_wd_mean; i++)
{
    var temp_arr = new Array();
    temp_arr['key'] = $("#tswes_2_"+i).val();
    temp_arr['value'] = $("#tswes_2_"+i).val();
    word_mean_arr.push(temp_arr);
}
console.log("Array to server length>" + word_mean_arr.length);
var jsonString = JSON.stringify(word_mean_arr);

How should I transfer data and what is the problem?

UPDATE 1: JSON.stringify(temp_arr) is [], but when console.log(word_mean_arr) I see whole structure of my array.

UPDATE 2: Replacing temp_arr['key'] with temp_arr[0], solves my problem. But still qurious how to send key->val.

Alex · Accepted Answer · 2014-05-03 14:52:18Z

1

Your temp_arr variable is initialized as an array, but then you work with it as with an object, accessing keys that it does not have.

This will solve the problem:

var temp_arr = {
    key: $("#tswes_2_"+i).val(),
    value: $("#tswes_2_"+i).val()
};

instead of this:

var temp_arr = new Array();
temp_arr['key'] = $("#tswes_2_"+i).val();
temp_arr['value'] = $("#tswes_2_"+i).val();

answered May 3, 2014 at 14:52

Alex

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Daniel W. · Accepted Answer · 2014-05-03 14:52:37Z

0

Simply don't use JSON.stringify, jQuery does encode the variables itself when using $.post.

var word_mean_arr = $('.tswes').serialize();
console.debug('sending: ');
console.debug(word_mean_arr);
$.post('./ajax2/myscript.php', { block_id: bl_id, wm_arr: word_mean_arr });

If it does not work, try different:

var word_mean_arr = [];
for (var i = 0; i <= this.n_of_wd_mean; i++)
{
    var temp_arr   = {};
    temp_arr.key   = $("#tswes_2_"+i).val();
    temp_arr.value = $("#tswes_2_"+i).val();

answered May 3, 2014 at 14:52

Daniel W.

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