Get specific key values as an array from array of object

Question

This is my code:

$a = array(
    array("a" => 1, "b" => 2),
    array("x" => 2, "a" => 2),
    array("d" => 100, "a" => 3, "b" => 2, "c" => 3)
);
$myArray = array();
foreach ($a as $arr) {
    $myArray[] = $arr['a'];
}
print_r($myArray);

So, I get

Array
(
    [0] => 1
    [1] => 2
    [2] => 3
)

Is there any other way to do this without for loop? like using one are two PHP array functions to get the same response.

The above is correct but still if there is any other better way to do this that would be appreciable! Because the same array $a in my code is required to be iterate many times. If I have any better way to do this so I can reduce another iteration( PHP still does iteration in built-in fns, I don't bother it).

possible duplicate of Is there a function to extract a 'column' from an array in PHP? — John Conde
– John Conde, Commented Apr 21, 2014 at 13:43
It's a shame you are not using PHP 5.5. It has a function specifically for this. — John Conde
– John Conde, Commented Apr 21, 2014 at 13:43

Alma Do · Accepted Answer · 2014-04-21 13:43:48Z

3

Yes (since you're on PHP 5.4, array_column() isn't an option),

$result = array_map(function($x)
{
   return $x['a'];
}, $a);

But note, this will still use loop internally (i.e. in the end it always be a loop)

answered Apr 21, 2014 at 13:43

Alma Do

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