Fatal error: Cannot use object of type User as array

Question

The users on the application are logged in by their e-mail. This e-mail is in a session. With this session I try to get more information of that user to print out there (sur)names and the avatar. When I do it in my navbar he's doing it all well but on the page itself it gives the following error: 'Fatal error: Cannot use object of type User as array'

What am i doing wrong?

PHP:

$user = new User();
$email = $_SESSION['email'];
$user->getUserInfoByEmail($email);
var_dump($user['avatar']);

FUNCTION:

public function getUserInfoByEmail($email)
{
    $db = new Db();
    $select = "SELECT * FROM tblusers WHERE email = '" . $_SESSION["email"] . "';";
    $result = $db->conn->query($select);
    return $data=$result->fetch_assoc();

}

The only error is in the var_dump, you are trying to access Object as an array. And now I see, that the answer was already added. So have a look at it and it's self-explanatory. — jPO
– jPO, Commented Apr 12, 2014 at 20:03

Sverri M. Olsen · Accepted Answer · 2014-04-12 20:03:04Z

15

It is because you are using the $user object as an array (as the error message makes perfectly clear).

Change:

var_dump($user['avatar']);

To this:

var_dump($user->avatar);

answered Apr 12, 2014 at 20:03

Sverri M. Olsen

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3 Comments

Marnix Verhulst Over a year ago

It's giving me 'null' as result.. but I don't get it. I'm doing exactly the same on the other place en that's working perfectly?

Sverri M. Olsen Over a year ago

@MarnixVerhulst If it gives you null then maybe it is because it actually is null? It can also be because avatar does not exist in the object. Try to var_dump($user); and see if the avatar property is defined in the class.

Marnix Verhulst Over a year ago

Thanks for the tip... Its working now :) sorry i didn't check that

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