Jquery check if array contains duplicate string

Question

How to check if array contains a duplicate string , i have validateArray = ['sa','sa','yu'] i have used the following function from SO but same not working for me.

checkDuplicate = function (reportRecipients) {
    if (reportRecipients.length > 1) {
        var recipientsArray = reportRecipients.toString().split(',');
        for (a in recipientsArray) {
            if(reportRecipients.indexOf(a) != reportRecipients.lastIndexOf(a)){
                return true;
                break;
            }
        }
    }
    return false;
}

possible duplicate of Easiest way to find duplicate values in a JavaScript array — adeneo
– adeneo, Commented Apr 10, 2014 at 6:04

MysticMagicϡ · Accepted Answer · 2014-04-10 06:20:41Z

27

This is working for me:

var reportRecipients = ['AAA', 'XYZ', 'AAA', 'ABC', 'XXX', 'XYZ', 'PQR'];
var recipientsArray = reportRecipients.sort(); 

var reportRecipientsDuplicate = [];
for (var i = 0; i < recipientsArray.length - 1; i++) {
    if (recipientsArray[i + 1] == recipientsArray[i]) {
        reportRecipientsDuplicate.push(recipientsArray[i]);
    }
}

Hope that helps.

answered Apr 10, 2014 at 6:20

MysticMagicϡ

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Comments

Midhun · Accepted Answer · 2018-06-21 06:13:20Z

1

Please try this, if the sort function is not working well :

    var all_list= ['sa','sa','yu'] 
    var duplicates_list = [];
    var unique_list = [];
    $.each(all_list, function(key, value){
            if($.inArray(value, unique_list ) == -1){
                unique_list.push(value);
            }else{
                if($.inArray(value, duplicates_list ) == -1){
                    duplicates_list.push(value);
                }
            }
    });

//duplicated elements 
console.log(duplicates_list )

answered Jun 21, 2018 at 6:13

Midhun

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Comments

James Risner · Accepted Answer · 2022-10-28 03:06:16Z

1

You can check if an array has duplicates using $.unique function on jQuery.

let len1 = myArray.length; //get the length of your array
let len2 = $.unique(myArray).length; //the length of array removing the duplicates

if (len1 > len2) {
  alert('Found duplicate');
} else {
  alert('Did not find duplicate');
}

edited Oct 28, 2022 at 3:06

James Risner

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answered Oct 23, 2022 at 17:47

Giorgos Michael

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1 Comment

VDWWD Over a year ago

This does not work, it is meant for DOM objects. See api.jquery.com/jQuery.uniqueSort

Karim AG · Accepted Answer · 2014-04-10 06:53:47Z

0

Take a look at this:

function getDistinctArray(arr) {
    var compareArray = new Array();
    if (arr.length > 1) {
        for (i = 0;i < arr.length;i++) {
            if (compareArray.indexOf(arr[i]) == -1) {
                compareArray.push(arr[i]);
            }
        }
    }
    return compareArray;
}

And here is a working fiddle

answered Apr 10, 2014 at 6:53

Karim AG

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Comments

Azhar · Accepted Answer · 2022-11-16 07:42:12Z

0

    var arr = [1, 2, 3, 4, 4];
    var chk = new Set();
    var duplicates = arr.filter(n => chk.size === chk.add(n).size);
    //console.log(duplicates); // [ 5 ]
    //console.log(duplicates.length); // 1
    if(duplicates.length > 0){
        alert('Duplicate Found');
        return false;
    }
    else{
        return true;
    }

This Working fine. it is the best shortest method .

answered Nov 16, 2022 at 7:42

Azhar

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Comments

VDWWD · Accepted Answer · 2023-09-29 08:54:21Z

0

A simple and clean solution

var fileredArray = myArray.filter(function (elem, index, self) {
    return index === self.indexOf(elem);
});

Demo:

var myArray = [10, 20, 30, 10];

//also works with strings (case sensitive!)
var myArray = ['Amsterdam', 'Paris', 'London', 'Paris'];

//check for duplicates
var fileredArray = myArray.filter(function (elem, index, self) {
    return index === self.indexOf(elem);
});

//show warning if 1 or more duplicate found
if (fileredArray.length < myArray.length) {
    alert('Duplicates found.')
}

//logging
console.log(myArray);
console.log(fileredArray);

answered Sep 29, 2023 at 8:54

VDWWD

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Comments

Bhargav Rao · Accepted Answer · 2016-10-25 09:03:38Z

-6

just use unique() method.

$.unique(reportRecipients);

https://api.jquery.com/jQuery.unique/

edited Oct 25, 2016 at 9:03

Bhargav Rao

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answered Oct 25, 2016 at 9:02

Aster

1

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