Curl with Loop using php

Question

I have a problem, I want to get data from another website and display it on my website using cURL.

For example, this is data from the other website which I would like to parse and display on my website.

<div class="users-name"> <a href='#'>User 1</a></div>
<div class="users-name"> <a href='#'>User 2</a></div>
<div class="users-name"> <a href='#'>User 3</a></div>
<div class="users-name"> <a href='#'>User 4</a></div>
<div class="users-name"> <a href='#'>User 5</a></div>
<div class="users-name"> <a href='#'>User 6</a></div>
<div class="users-name"> <a href='#'>User 7</a></div>
<div class="users-name"> <a href='#'>User 8</a></div>

Currently I'm getting first row of data, but now I want to get all of this data.
I have tried this so far:

$curl = curl_init('www.domain.com/search.php');
curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);

$page = curl_exec($curl);

if(curl_errno($curl)) // check for execution errors
{
    echo 'Scraper error: ' . curl_error($curl);
    exit;
}

curl_close($curl);

$regex = '/<div class="users-name">(.*?)<\/div>/s';

if(preg_match($regex, $page, $list))
    print_r($list[0]);
else
    print "Not found";

What do you mean? You are explicitly calling first match in the list with print_r($list[0]); — arma
– arma, Commented Apr 2, 2014 at 15:07
If you change print_r($list[0]); to print_r($list); you should see the entire contents of the array. It should contain the other matches. — AeroX
– AeroX, Commented Apr 2, 2014 at 15:08

Ritesh Chandora · Accepted Answer · 2014-04-02 15:16:27Z

1

Replace

preg_match($regex, $page, $list)

with

preg_match_all($regex, $page, $list)

preg_match stops after the first match. preg_match_all gets all the matches.

answered Apr 2, 2014 at 15:16

Ritesh Chandora

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2 Comments

Ritesh Chandora Over a year ago

@user3487256 in StackOverflow if you find answer correct please vote up and accept it as correct answer.

user3487256 Over a year ago

i have one more problem, can i get more than one div in one time. for example: <div class="users-name"> <a href='#'>User 1</a></div> i'm getting all this now i also want user address. its another div <div class="users-name-address"> <a href='#'>users 1 address</a></div>

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