PHP: Unexplainable parse errors

Question

Uhm, I'd like to think of myself as a pretty experienced php coder but I actually can not for the life of me figure out what is wrong with my code. So I wrote this little script to create a nice, colourful background, maybe throw in an easter egg every now and then. Nothing too serious, just having a little fun. Either way it works fine, it just throws pretty random errors.

Code looks like this: http://pastebin.com/5ndL1E7J

<?
header("Content-Type: image/png");
header("Expires: Mon, 26 Jul 1997 05:00:00 GMT");
header("Last-Modified: " . gmdate("D, d M Y H:i:s") . " GMT"); 
header("Cache-Control: no-store, no-cache, must-revalidate"); 
header("Cache-Control: post-check=0, pre-check=0", false);
header("Pragma: no-cache");

$bgtime = file_get_contents('bgtime');

if( $bgtime <= time() ) {
    file_put_contents( 'bgtime', time() + 5 );
    $im = imagecreate( 1920, 955 );
    imagecolorallocate( $im, 255, 255, 255 );
    $red = imagecolorallocatealpha( $im, 136, 34, 34, 235);
    $green = imagecolorallocatealpha( $im, 34, 136, 34, 235);
    $blue = imagecolorallocatealpha( $im, 34, 34, 136, 235);

    for( $x=0; $x<88; $x++ ) {
        for( $y=0; $y<44; $y++ ) {      
            if( mt_rand( 0, 1 ) ) {
                $col = mt_rand( 0, 100 );
                if( $col < 90 ) {
                    imagefilledrectangle( $im, $x*22-10, $y*22-10, $x*22+10, $y*22+10, $green );
                } else if( $col < 98 ) {
                    imagefilledrectangle( $im, $x*22-10, $y*22-10, $x*22+10, $y*22+10, $blue );
                } else {
                    imagefilledrectangle( $im, $x*22-10, $y*22-10, $x*22+10, $y*22+10, $red );
                }
            }
        }
    }
    imagepng( $im, 'background.png' );
    imagepng( $im );
    imagedestroy( $im );

} else if( mt_rand( 0, 10 ) == 1 ) {
    $texts = [ "#<<_ Over#######>>> 9000", "#<<_ Game#######>>>_ Over" ];

    include '../fonts/pokebet.charray';

    $im = imagecreatefrompng( 'background.png' );
    $text = str_split( $texts[array_rand($texts)] );
    $red = imagecolorallocatealpha( $im, 136, 34, 34, 235);

    $offx = 0;
    $offy = 0;

    foreach( $text as $char ) {
        if( $char == '#' ) {
            $offx += 9;
            $offy = 0;
        } else if( $char == ">" ){
            $offx += 1;
        } else if( $char == "<" ) {
            $offx -= 1;
        } else if( $char == "_") {
            $offy += 5;
        } else if( $char == " ") {
            $offy += 1;
        } else {
            $offy -= $charray[$char][2];

            foreach( $charray[$char][0] as $pixel ) {
                $x = $pixel[0] + $offx;
                $y = $pixel[1] + $offy;

                imagefilledrectangle( $im, $x*22-10, $y*22-10, $x*22+10, $y*22+10, $red );
            }

            $offy += $charray[$char][1];
        }
    }
    imagepng( $im );
    imagepng( $im );
} else {
    include 'background.png';
}

?>

Error looks like this, claimed lines and t_strings differ greatly with every error:

PHP Parse error:  syntax error, unexpected '\xdeu\xdc\x81\xcb\xd7\xb59jb\xe5\xae\xfa' (T_STRING) in /var/www/inf1/images/background.png on line 31, referer: http://inf1.****.nl/

Roman Hocke · Accepted Answer · 2014-03-30 10:00:01Z

1

include 'background.png'; pastes the PNG image in the PHP code and tries to parse it as PHP. That is not possible, of course. You probably need something like fpassthru:

$fp = fopen('background.php', 'rb');
fpassthru($fp);
fclose($fp);

answered Mar 30, 2014 at 10:00

Roman Hocke

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3 Comments

Samuel Willems Over a year ago

Yea facepalm I didn't really pay attention to that. I guess I assumed it would just be crammed in there as if it had no php tags. I mean in a way it does that, but I couldn't possibly tell what kind of potential code the image could contain xD

Samuel Willems Over a year ago

Yeup that seems to have fixed it. Thanks a bunch man, I'm such a derp, it would've taken me forever to realise that!

Roman Hocke Over a year ago

Congratulations, You've just gained a few experience points :-)

majidarif · Accepted Answer · 2014-03-30 10:21:36Z

1

Try changing the include 'background.png' to:

base64_encode(file_get_contents("background.png"));

and echo it out to a <img src=...

Like:

$imageData = base64_encode(file_get_contents("background.png"));

$src = 'data: '.mime_content_type($image).';base64,'.$imageData;

echo '<img src="',$src,'">';

Or maybe something along the lines of:

$file = 'background.png';

if (file_exists($file)) {
    header('Content-Type: image/png');
    header('Content-Length: ' . filesize($file));
    ob_clean();
    flush();
    readfile($file);
    exit;
}

Or simply:

$file = 'background.png';
$type = 'image/png';
header('Content-Type:'.$type);
header('Content-Length: ' . filesize($file));
readfile($file);

The errors are happening because of special characters from the image data being read as PHP code.

edited Mar 30, 2014 at 10:21

answered Mar 30, 2014 at 10:01

majidarif

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2 Comments

Samuel Willems Over a year ago

Oh yea that's totally a valid thing these days... Let me see if I can work that out .-.

Samuel Willems Over a year ago

Wow, thanks for the barrage of options, sincerely, but I guess just using the header 'image/png' and echoing the images contents works fine. Oh yea but thanks for the base64 encode thing, I almost forgot about that, it's fun :3

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