Javascript declare multiple variables with the same values

Question

Maybe I should use some kind of loop or something. But I don't have any idea how to declare this, excluding do it manually.

Is there any solution that will have only a few lines for all of this. Because, there should be 100 variable, despite I only presented 5, I didn't want to type all night.

a1=1; a2=1; a3=1; a4=1; a5=1;

function myfn1() {
a1++;
//unique function code
}
function myfn2() {
a2++;
//unique function code
}
function myfn3() {
a3++;
//unique function code
}
function myfn4() {
a4++;
//unique function code
}
function myfn5() {
a5++;
//unique function code
}

The reason is I don't know how to declare a fn with an array :( — user3392725
– user3392725, Commented Mar 18, 2014 at 1:39
So you have 100 unique functions? Is it safe to assume that they're actually the same, except for the variable they use? If so, you can eliminate all that repetition. — cookie monster
– cookie monster, Commented Mar 18, 2014 at 1:55

Tyler McGinnis · Accepted Answer · 2014-03-18 01:39:48Z

Although this isn't answering your question, I think this approach will help you more in the long run (and probably in the short run too). Check out using an array, which is just a collection of data. Check out the following code.

var arr = [];
for(var i =0; i <= 100; i++){
  arr[i] = i;
}

this gives you a collection like this [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99, 100] that you can then manipulate, etc etc.

*edit or if you want them all to have the same value, then

var arr = [];
for(var i =0; i <= 100; i++){
  arr[i] = 1;
}

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