Strings Array error

Question

Tell me how to implement this example, understand with List view , in strings :

<string name="ml350">300</string>
<string name="ml400">400</string>
<string name="ml600">600</string>
<string name="ml800">800</string>
<string name="ml1000">1000</string>

.

public static final String[] descriptions = new String[] {
        "300",
        "400", "600",
        "800","1000" };

ListView listView;
List<RowItem> rowItems;

    rowItems = new ArrayList<RowItem>();
    for (int i = 0; i < descriptions.length; i++) {
        //RowItem item = new RowItem(images[i], titles[i], descriptions[i]);
        RowItem item = new RowItem(R.drawable.ic_untitled_2, descriptions[i], descriptions[i]);
        rowItems.add(item);
    }

    listView = (ListView) findViewById(R.id.list);
    CustomListViewAdapter adapter = new CustomListViewAdapter(this,
            R.layout.listview_item_row, rowItems);
    listView.setAdapter(adapter);
    listView.setOnItemClickListener(this);

the problem is that when I try to substitute:

public static final String[] descriptions = new String[] {
        R.strings.300,
       R.strings.400, R.strings.600,
        R.strings.800,R.strings.1000 };

I receive an error.

consider making descriptions as non-static variable. Just declare the descriptions variable. and initialize it in onCreate() like descriptions = getResources().getStringArray(int). but here you have just declared Strings, not a string-array... — Gopal Gopi
– Gopal Gopi, Commented Mar 16, 2014 at 10:33

Shayan Pourvatan · Accepted Answer · 2014-03-16 11:00:50Z

1

you must use:

R.strings.ml350,
R.strings.ml400,
R.strings.ml600,
R.strings.ml800,
R.strings.ml1000

instead of :

R.strings.300,
R.strings.400,
R.strings.600,
R.strings.800,
R.strings.1000

and you need:

 getResources().getString("your key");

for first:

300 is a value of ml350, so you need key of that for accessing the value.

second:

R.string.Key return id of String but you need Value of String so you must access that with getResources().getString() method

and better way is create one array and call that in your activity.

//Edit

so your code must be like:

public static final String[] descriptions = new String[] {
        getResources().getString(R.strings.ml350),
        getResources().getString(R.strings.ml400),
        getResources().getString(R.strings.m1600),
        getResources().getString(R.strings.ml800,
        getResources().getString(R.strings.m11000) };

and you must call this after initializing your view because this need context of your layout, so if you call before onCreate() you got NPE

edited Mar 16, 2014 at 11:00

answered Mar 16, 2014 at 10:23

Shayan Pourvatan

11.9k4 gold badges44 silver badges63 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

comSaaxov Over a year ago

Thanks corrected his inattention, but it did not solve the problem

comSaaxov Over a year ago

thank you! helped this code :

final  String [] descriptions =  new  String []  {                 getResources().getString(R.string.ml350),                 getResources().getString(R.string.ml400),                 getResources().getString(R.string.ml600),                 getResources().getString(R.string.ml800),                 getResources().getString(R.string.ml1000)};

Shayan Pourvatan · Accepted Answer · 2014-03-16 10:41:06Z

1

<string-array name="system">
   <item>300</item>
   <item>400</item>
   <item>600</item>
   <item>800</item>
   <item>1000</item>
</string-array>

you can create an array in your xml and then call

 String[] descriptions  = getResources().getStringArray(R.array.your_string_array) //in example is system

edited Mar 16, 2014 at 10:41

Shayan Pourvatan

11.9k4 gold badges44 silver badges63 bronze badges

answered Mar 16, 2014 at 10:25

Matej Špilár

2,6773 gold badges19 silver badges30 bronze badges

1 Comment

Matej Špilár Over a year ago

getResources() is not a static method. You need an instance of the View to call it ...

Nathua · Accepted Answer · 2014-03-16 10:32:59Z

0

R.strings.300 returns int type but your array requires String type, that's why you get error.

edited Mar 16, 2014 at 10:32

answered Mar 16, 2014 at 10:26

Nathua

8,8345 gold badges35 silver badges42 bronze badges

Collectives™ on Stack Overflow

Strings Array error

3 Answers 3

2 Comments

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

2 Comments

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related