Convert a Php array to json format

Question

I have an array like this,

Array
    (
        [0] => 1
        [1] => naveen
    )

    Array
    (
        [0] => 2
        [1] => bos
    )

I am using a csv upload to insert data's to the mongodb

while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {           
        echo "<pre>";
        print_r($data);         
        echo "</pre>";
}

i want to convert the array into a json format, i have tried the json_encode($data); but it is coming like this

["1","naveen"]

["2","bos"]

What i want to do make this array as json encoded format

Where i will read the csv file. i have a upload.php there i write the html form and action to a slim function. inside that function i would add the read the csv and inert to mongo db? — Naveenbos
– Naveenbos, Commented Mar 13, 2014 at 5:40

John Conde · Accepted Answer · 2014-03-12 12:46:56Z

4

You need to put it all into one array and then json encode it:

$array = array();
while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {           
    $array[] = $data;
}
$json = json_encode($array);

answered Mar 12, 2014 at 12:46

John Conde

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6 Comments

Neil Lunn Over a year ago

Please spread the word that the reverse json_decode is the usual answer to "how do I write this query in PHP".

Naveenbos Over a year ago

Hi John Conde Thankyou for your reply i am getting like this [["1","naveen"]][["1","naveen"],["2","bos"]], is it possible to make the array {"1":"naveen"},{"2":"bos"} like this?

John Conde Over a year ago

Try casting the arrays to objects: $array[] = (object) $data;

Naveenbos Over a year ago

I have tried this some changes but not exact one [{"0":"1","1":"naveen"},{"0":"2","1":"bos"}]

John Conde Over a year ago

That is how it will look because it is in one array, hence the array syntax around the objects.

|

Naveenbos · Accepted Answer · 2014-03-12 14:23:17Z

0

Yes finally make it work.

        $keys="";
        $result=array();
        while (($data = fgetcsv($handle, 1000, ",")) !== FALSE) {
            if($keys==""){
                $keys = $data;
            }else{
                $output = array();          
                for ($i=0; $i <count($keys) ; $i++) { 
                    $output[$keys[$i]]=$data[$i];

                }
                array_push($result, $output);
            }

        }
        echo "<pre>";
        print_r(json_encode($result));
        echo "</pre>";

Got Output Like below

[{"id":"1","name":"naveen"},{"id":"2","name":"bos"}]

answered Mar 12, 2014 at 14:23

Naveenbos

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