for this list ,
l=[i for i in range(1,100)]
How can i restrict to print only 1st 20 elements.
What i am trying to do is ,
>>> counter=0
>>> for index , i in enumerate(l):
... if counter==20:
... break
... print index , i
... counter+=1
...
Is there is another way to do this without using counter variable ?
Use a sliced list, like this
l=[i for i in range(1,100)]
for index, i in enumerate(l[:20]):
print index, i
Or you can use itertools.islice, to avoid generating entire list and instead iterate over xrange as long as you want, like this
from itertools import islice
for index, i in enumerate(islice(xrange(1, 100), 20)):
print index, i
Nishant N.'s answer is the probably the best. But your code would also have worked had you changed your if statement to read
if i == 20:
Just in case you wondered why it wasn't working (also you would have needed to set counter to 0 before the code you posted, but I accept that may just have been omitted.
