Underscore how to use the each and sort multiple array of objects

Question

I have 2 sets in an array, each of these sets is an array of objects. I'd like to sort both of them using _.each and return a sorted object with the following:

var O1 = [{'name':'one'}, {'name':'two'}, {'name':'three'}, {'name':'four'}, {'name':'five'}, {'name':'six'}];
var O2 = [{'name':'rat'}, {'name':'cat'}, {'name':'lion'}, {'name':'tiger'}, {'name':'dog'}, {'name':'horse'}];

var sortIt = [O1, O2];

_.each(sortIt, function(item){
    item = _.sortBy(item, function(arr){
        return arr.name;
    })
    return item;
})

console.log(O1, "\n", O2); //nothing changed!

... but, apparently, nothing changes. The question is, what should be the proper approach?

Live Demo

raina77ow · Accepted Answer · 2014-02-05 11:52:42Z

2

First and foremost, it's kind of useless checking the values of O1 and O2 variables after the sorting process - they won't change. See, _.sortBy doesn't order the given array in place (as native Array#sort does), instead it returns a new (sorted) copy.

Second, it makes little sense to return anything from _.each iterator function - it'll just be ignored.

Finally, to adjust the specific element of a list, you'll need to address that element; just reassigning some value to a param variable (item in your code) won't be enough.

Here's one approach to do what you want:

var sortIt = [O1, O2];
_.each(sortIt, function(item, index, list) {
    list[index] = _.sortBy(item, function(arr) {
        return arr.name;
    });
})

console.log(sortIt); // something is definitely changed now!

Demo.

edited Feb 5, 2014 at 11:52

answered Feb 5, 2014 at 11:39

raina77ow

107k16 gold badges205 silver badges240 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Underscore how to use the each and sort multiple array of objects

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related