var items = [
{
"id": 376,
"name": "b"
},
{
"id": 253,
"name": "f"
},
{
"id": 236,
"name": "c"
},
{
"id": 235,
"name": "e"
},
{
"id": 165,
"name": "a"
},
{
"id": 26,
"name": "d"
},
{
"id": 24,
"name": "d"
}
]
How can i sort array by name?
Since you are using strings try
items.sort(function (o1, o2) {
return o1.name.localeCompare(o2.name)
});
console.log(items)
There's a good example of sorting on a key here.
The example given in that answer looks like this:
items.sort(function(a, b){
var keyA = new Date(a.name),
keyB = new Date(b.name);
// Compare the 2 dates
if(keyA < keyB) return -1;
if(keyA > keyB) return 1;
return 0;
});
This is an array of objects. You'll need to write your own compare function.
function compare(a,b) {
if (a.name < b.name)
{
return -1;
}
if (a.name > b.name)
{
return 1;
}
return 0;
}
Then sort it like so:
items.sort(compare);
Here you go:
function byName(a, b){
var nameA = a.name.toLowerCase();
var nameB = b.name.toLowerCase();
return ((nameA < nameB) ? -1 : ((nameA > nameB) ? 1 : 0));
}
array.sort(byName);
More about .sort()
you can use this simple code:
myarray.sort(function(a, b){
var keyA = new Date(a.updated_at),
keyB = new Date(b.updated_at);
// Compare dates
if(keyA < keyB) return -1;
if(keyA > keyB) return 1;
return 0;
});
This Could Work
function SortByName(a, b){
var aName = a.id;
var bName = b.id;
return ((aName < bName) ? -1 : ((aName > bName) ? 1 : 0));
}
items.sort(SortByName)
