Regex - Shell scripting

Question

I have a file which looks like this :

{
    "0" : NumberLong(654654),
    "1" : NumberLong(31321),
    "2" : NumberLong(44534564),
    "3" : NumberLong(464564645),
}

My output should be something like this :

I tried to do this :

grep -Po ' NumberLong\("\K[^"]*' file

But it doesn't seem to work for me.

Rakesh KR · Accepted Answer · 2014-01-17 19:26:04Z

2

Try

grep -Po ' NumberLong\(\K\d+' file

answered Jan 17, 2014 at 19:26

Rakesh KR

6,5475 gold badges45 silver badges58 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

anubhava · Accepted Answer · 2014-01-17 19:25:06Z

2

Try this grep:

grep -Po ' NumberLong\(\K[^)]*' file
654654
31321
44534564
464564645

OR this grep:

grep -Po ' NumberLong\(\K\d+' file
654654
31321
44534564
464564645

answered Jan 17, 2014 at 19:25

anubhava

790k67 gold badges603 silver badges671 bronze badges

signjing · Accepted Answer · 2017-04-24 10:19:30Z

0

Use this: grep -Po "(?<=\()[^)]+" data.txt 654654 31321 44534564 464564645

answered Apr 24, 2017 at 10:19

signjing

984 bronze badges