Use php include within a php code

Question

I have a php code that will create a txt file, the problem I'm having is adding is the content of the txt file.

I want to include it from an external file.

This is the code i have used so far:

<?php
$data = $_POST;
$time = time();
$filename_prefix = 'file/evidence_file';
$filename_extn   = 'txt';

$filename = $filename_prefix.'-'.$time.'-'.uniqid().'.'.$filename_extn;

if( file_exists( $filename ) ){
 # EXTREMELY UNLIKELY, unless two forms with the same content and at the same time are submitted
  $filename = $filename_prefix.'-'.$time.'-'.uniqid().'-'.uniqid().'.'.$filename_extn;
 # IMPROBABLE that this will clash now...
}

if( file_exists( $filename ) ){
 # Handle the Error Condition
}else{
  file_put_contents( $filename , '<?php include("text.php"); ?>' );
}
?>

The problem is using the php include within the current code! All that it prints in the txt file is:

<?php include("text.php"); ?>

How can I get it to display the content of text.php?

Also the text.php file contains php code.

file_get_contents() instead of include()

Mike B
– Mike B

2014-01-02 20:31:48 +00:00
Commented Jan 2, 2014 at 20:31 — Mike B
– Mike B, Commented Jan 2, 2014 at 20:31
Do you want to execute the php file as well?

jeroen
– jeroen

2014-01-02 20:32:08 +00:00
Commented Jan 2, 2014 at 20:32 — jeroen
– jeroen, Commented Jan 2, 2014 at 20:32

Community · Accepted Answer · 2023-11-17 19:42:58Z

4

As said, you can use file_gets_content to get the content of the file.

But if you want to first execute the file, as it's php code, and get the resulting content and put in the file then (I guess it's what you want), you have to use the buffer :

ob_start();

include('text.php');

$content = ob_get_contents();
ob_end_clean();

file_put_contents($filename , $content);

This way, the php file is executed and it's resulted content is passed to the file. If you want to know more about ouput control functions, here's the documentation.

edited Nov 17, 2023 at 19:42

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answered Jan 2, 2014 at 20:39

yachaka

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Comments

Community · Accepted Answer · 2023-11-17 20:33:26Z

0

Currently, you're just putting in a string to the file_put_contents, so it will take what you put in literally, and anyway, include() isn't what you want anyway

include("text.php"); loads the php file and execute its contents when put inside PHP, I don't think you want to do that. Use file_get_contents() instead, like this:

file_put_contents($filename,file_get_contents("text.php"));

edited Nov 17, 2023 at 20:33

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answered Jan 2, 2014 at 20:35

scrblnrd3

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Comments

matewka · Accepted Answer · 2014-01-02 20:38:10Z

0

I guess you should do it like that

file_put_contents( $filename , '<?php '. file_get_contents("text.php") .'?>' );

file_get_contents function returns the file contents as a string while include literally includes and evaluates the file. Since your file is a PHP file and you only want to include it as a string my solution should be fine.

answered Jan 2, 2014 at 20:38

matewka

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Community · Accepted Answer · 2023-11-17 20:13:27Z

-1

Use file_get_contents function instead of include.

file_put_contents($filename, file_get_contents("text.php"));

Use include when you want the included code to be executed, not used as a text.

edited Nov 17, 2023 at 20:13

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answered Jan 2, 2014 at 20:32

$fracz's user avatar$

fracz

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1 Comment

sjagr Over a year ago

You should add code to explain how to use file_get_contents (along with the explanation), perhaps explain why include isn't appropriate in this use case scenario, otherwise this is more of a comment than an answer. Edit: Better

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