20

I'm not sure if it is possible but what I want to do is to run a bash command and storing the output in a variable AND display it as if I launched the command normally. Here is my code:

VAR=`svn checkout $URL`

So I want to store the output in VAR and still see the result (and because svn checkout takes a long time, I can't do echo $VAR just after..)

Thanks

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2 Answers 2

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26

If the command is run from a terminal, you can do:

VAR=$(svn checkout $URL | tee /dev/tty)
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3 Comments

Gah, beat me to it by seconds!
Maybe because I tested the above with v=$(for i in $(seq 20); do echo $i; sleep 0.2; done | tee /dev/tty), and you used sleep 1? :-)
Note that this does not work when executed by Github Actions due to the lack of a tty (see github.com/actions/runner/issues/241 )
2

You don't have to call the external tee:

VAR=$(svn checkout $URL) && echo $VAR

or even:

VAR=$(svn checkout $URL); echo $VAR
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2 Comments

I think the idea was that svn takes a long time, and the OP wanted to see the output of the svn command in realtime, instead of after it ended. He even says so in the question :-)
I think I need to get some help on literacyoverflow!

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