how to copy and rename file with for loop in bash script?

Question

How I can copy all file *.html to *.php with For loop?

help me...

this my script :

#!/bin/bash
list="$(ls *.html)"
for i in "$list"
do
  newname=$(ls "$i" | sed -e 's/html/php/')
  cat beginfile > "$newname"
  cat "$i" | sed -e '1,26d' | tac | sed -e '1,21d' | tac >> "$newname"
  cat endfiel >> "$newname"
done

or you have another ide ?

Chris Dodd · Accepted Answer · 2013-12-09 23:57:34Z

6

for f in *.html; do cp $f ${f%.html}.php; done

answered Dec 9, 2013 at 23:57

Chris Dodd

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janos · Accepted Answer · 2013-12-17 13:43:17Z

3

Here you go:

for i in *.html; do mv "$i" "${i%.html}.php"; done

In RedHat Linux and derivatives there is a rename utility that simplifies this to:

rename .html .php *.html

In Debian Linux and derivatives there is a rename utility that simplifies this to:

rename 's/.html$/.php/' *.html

Check man rename or rename --help to see how to use the implementation you have. Sometimes the utility is called rename.pl instead of simply rename.

edited Dec 17, 2013 at 13:43

answered Dec 9, 2013 at 23:56

janos

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Reinstate Monica Please · Accepted Answer · 2013-12-10 00:34:48Z

1

Can omit the for loop altogeather if you have perl packages installed.

#!/bin/bash
rename 's/html/php/' *.html

answered Dec 10, 2013 at 0:34

Reinstate Monica Please

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