Javascript how to transform an array of objects

Question

I have an array of company objects and now I want to create a comma separated string of "companyId"s

 var company ={companyId:'', companyName:''}, 
 var companies: [company1, company2, ..]

 expectedStringResult ="companyId1,companyId2,companyId3"

I see this example in SO:

Create comma-delimited string

But the answer assumes you have strings in your array and not objects like company, is there a way to neatly accomplish this without a for loop in javascript/jquery? (like you apply transform function in Java guava library)

Edit: I ended up using underscoreJS pluck function:

 _.pluck(companies, "companyId").join()

this does not crash if companies is null and much clean

But the accepted answer below with jQuery also works well.

Yury Tarabanko · Accepted Answer · 2013-12-05 15:19:29Z

3

companies.map(function(item){return item.companyId;}).join(',');

Or for old browsers

$.map(companies, function(item){return item.companyId;}).join(',');

edited Dec 5, 2013 at 15:19

answered Dec 5, 2013 at 14:39

Yury Tarabanko

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10 Comments

Spring Over a year ago

tnx and this will return a string? and as a reminder I don't want my original companies array is modified

Yury Tarabanko Over a year ago

This will return a string. The original array will remain unmodified.

jbabey Over a year ago

I think join uses a comma as a delimiter by default (you don't need to specify it)

Yury Tarabanko Over a year ago

@Spring If you have underscore use _.pluck(companies, "companyId").join() :)

Yury Tarabanko Over a year ago

No difference actually just more specific method to project data in arrays.

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Tushar Gupta - curioustushar · Accepted Answer · 2013-12-05 14:39:59Z

1

Try $.makeArray()

Convert an array-like object into a true JavaScript array.

var expectedStringResult = $.makeArray(company.companyId).join();

answered Dec 5, 2013 at 14:39

Tushar Gupta - curioustushar

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2 Comments

Spring Over a year ago

it returns nothing :)

Spring Over a year ago

srry no time for that

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