.test {
width:80px;
height:50px;
background-color:#808080;
margin:20px;
}
HTML -
<div class="test">Click Here</div>
In JavaScript i want to get margin:20px
5 Answers
For modern browsers you can use getComputedStyle:
var elem,
style;
elem = document.querySelector('.test');
style = getComputedStyle(elem);
style.marginTop; //`20px`
style.marginRight; //`20px`
style.marginBottom; //`20px`
style.marginLeft; //`20px`
margin is a composite style, and not reliable cross-browser. Each of -top -right, -bottom, and -left should be accessed individually.
9 Comments
Chinmay235
Showing blank when i am using
alert(style.margin);
Kareem Hashem
include jQuery and use this is simpler and better $('.test').css( "margin" );
VisioN
@Chinmay What browser do you use?
Chinmay235
Latest browser
Mozilla 25.0.1Chinmay235
hello @zzzzBov your code also working in chrome but not working in mozilla. :(
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The accepted answer is the best way to get the computed values. I personally needed the pre-computed value. Say for instance 'height' being set to a 'calc()' value. I wrote the following jQuery function to access the value from the style sheet. This script handles nested 'media' and 'supports' queries, CORS errors, and should provide the final cascaded precomputed value for accessible properties.
$.fn.cssStyle = function() {
var sheets = document.styleSheets, ret = [];
var el = this.get(0);
var q = function(rules){
for (var r in rules) {
var rule = rules[r];
if(rule instanceof CSSMediaRule && window.matchMedia(rule.conditionText).matches){
ret.concat(q(rule.rules || rule.cssRules));
} else if(rule instanceof CSSSupportsRule){
try{
if(CSS.supports(rule.conditionText)){
ret.concat(q(rule.rules || rule.cssRules));
}
} catch (e) {
console.error(e);
}
} else if(rule instanceof CSSStyleRule){
try{
if(el.matches(rule.selectorText)){
ret.push(rule.style);
}
} catch(e){
console.error(e);
}
}
}
};
for (var i in sheets) {
try{
q(sheets[i].rules || sheets[i].cssRules);
} catch(e){
console.error(e);
}
}
return ret.pop();
};
// Your element
console.log($('body').cssStyle().height);
1 Comment
kshetline
I just tried this code with a very simple case, and it worked, but there's something that doesn't make sense to me. The code
ret.concat(q(rule.rules || rule.cssRules)); looks like it expects something to be returned from the q function, but that function has no return value. I'm guessing that the real work is done by accumulating values in ret, but you would be accumulating undefined values this way.Using jQuery:
$('.class').css( "backgroundColor" );
Comments
Another approach (still experimental) could be computedStyleMap:
const computedStyleMap = document.getElementById('my-id').computedStyleMap();
computedStyleMap.get('overflow-x'); // {value: 'scroll'}
computedStyleMap.has('padding-right'); // false
computedStyleMap.entries(); // Iterator {}
1 Comment
I've just released an npm package for this purpose exactly. You can find it here on npm or github:
npm: https://www.npmjs.com/package/stylerjs
github: https://github.com/tjcafferkey/stylerjs
you would use it like so
var styles = styler('.class-name').get(['height', 'width']);
and styles would equal
{height: "50px", width: "50px"}
So you could just get the values like so
var height = styles.height;
1 Comment
Jan
Works like a charm. I removed the "export default " on the first line and added a
<script src="js/styler.js"></script> to get it to work.
getComputedStyle.