Wordpress php else if statement with advanced custom fields

Question

I'm trying to make an if-else-statement which works by going if there is a link print it around the name.

I have the below code which is almost there. However, the link is being printed above the text ranther than being an actual link.

<?php if( the_sub_field('corporate_link') ){ ?>

<a href="<?php the_sub_field('corporate_link'); ?>" 
   target="_blank" 
   title="<?php the_field('corporate_name'); ?>"><?php the_field('corporate_name'); ?></a>

<?php } else { ?>

<?php the_sub_field('corporate_name'); ?>

<?php } ?>

Any thoughts on how to make it link instead of printing the link if it`s there?

So what im looking to acheive is if there is a link print this

 <a href="<?php the_sub_field('corporate_link'); ?>">Coprate Name</a>

If there isn't a link it just shows the corporate name.

I think the_sub_field('corporate_link') is not return any value, and it's always false. But this function print to output buffer. Because, you get it above — Sergey
– Sergey, Commented Dec 4, 2013 at 11:41
What do you get when you print the_sub_field('corporate_link') — Ghazanfar Mir
– Ghazanfar Mir, Commented Dec 4, 2013 at 11:44

Pranita · Accepted Answer · 2013-12-04 11:57:02Z

3

use get_sub_field('corporate_link') instead of the_sub_field('corporate_link')

<?php 
   $corporate_link = get_sub_field('corporate_link');
   $corporate_name = get_sub_field('corporate_name');

  if( $corporate_link != '' ){ ?>

   <a href="<?php echo $corporate_link; ?>" 
   target="_blank" 
   title="<?php echo $corporate_name; ?>"><?php echo $corporate_name; ?></a>

 <?php } else { ?>

 <?php echo $corporate_name; ?>

<?php } ?>

answered Dec 4, 2013 at 11:57

Pranita

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Comments

Alexis Pigeon · Accepted Answer · 2013-12-04 12:24:17Z

0

use get_sub_field() and get_field() instead of the_sub_field() and the_field()

edited Dec 4, 2013 at 12:24

Alexis Pigeon

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answered Dec 4, 2013 at 11:57

Valery Statichny

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