Java: converting char arrays to int

Question

so i am trying to convert an array of 3 characters to an integer. Here is what i have so far:

   char[] characters = {0, 1, 2}; 
   int number = Integer.parseInt(new String(characters));
   System.out.println(number);

however this prints the error:

Exception in thread "main" java.lang.NumberFormatException: For input string: "�"
    at java.lang.NumberFormatException.forInputString(NumberFormatException.java:65)
    at java.lang.Integer.parseInt(Integer.java:481)
    at java.lang.Integer.parseInt(Integer.java:527)
    at usemyinteger.UseMyInteger.main(UseMyInteger.java:41)

Java Result: 1

Suresh Atta · Accepted Answer · 2013-11-26 05:00:26Z

3

  char[] characters = {0, 1, 2};

Because now 0 1 2 are the integer literals , taking as the ASCII code for the character's .Not the actual characters '0' '1' '2'

should be

  char[] characters = {'0', '1', '2'};

answered Nov 26, 2013 at 5:00

Suresh Atta

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1 Comment

nfoggia Over a year ago

that would be the problem. Thank you for your help

Liubing · Accepted Answer · 2013-11-26 05:09:25Z

1

For your good, please add 2 lines to print tmp string, it will help you to find real problem.

char[] characters = {0, 1, 2};
String tmp=new String(characters);
System.out.println("tmp = " + tmp);
int number = Integer.parseInt(tmp);
System.out.println(number);

And you will see tmp is unreadable string, now you should know you missed "'".

answered Nov 26, 2013 at 5:09

Liubing

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