I have an associative array where keys are search strings and values are replacement strings.
$list = ['hi' => 0, 'man' => 1];
$string = "hi man, how are you? man is here. hi again."
It should produce:
$final_string = "0 1, how are you? 1 is here. 0 again."
How can I achieve this?
Off of the top of my head:
$find = array_keys($list);
$replace = array_values($list);
$new_string = str_ireplace($find, $replace, $string);
$keys should be $replace.
str_replace(), str_ireplace()
$replace = array_values($list); call to array_values is not necessary, you can just pass the $list array to str_replace.Can be done in one line using strtr().
Quoting the documentation:
If given two arguments, the second should be an array in the form
array('from' => 'to', ...). The return value is a string where all the occurrences of the array keys have been replaced by the corresponding values. The longest keys will be tried first. Once a substring has been replaced, its new value will not be searched again.
To get the modified string, you'd just do:
$newString = strtr($string, $list);
This would output:
0 1, how are you? 1 is here. 0 again.
preg_replace may be helpful.
<?php
$list = Array
(
'hi' => 0,
'man' => 1
);
$string="hi man, how are you? Man is here. Hi again.";
$patterns = array();
$replacements = array();
foreach ($list as $k => $v)
{
$patterns[] = '/' . $k . '/i'; // use i to ignore case
$replacements[] = $v;
}
echo preg_replace($patterns, $replacements, $string);
$newString = str_replace(array_keys($list), array_values($list), $string);or$newString = strtr($string, $list);