Filter an array of objects within an object

Question

I have the following;

var room = function(){
    this.entities = new Array();
}
var myRoom = new room();

I also have a bunch of entites like this;

var entity = function(){
    this.title = "A pillow";
    this.noun = "pillow";
}

I can push many entities into the myRoom.entities array.

Now I want to check to see whether a room contains a particular entity based on its noun.

I've tried something like this;

var objPillow = myRoom.filter(function (object) { return object.entities.noun == "pillow" });

But it doesn't work.

How are you pushing entities into myRoom.entities? What does “doesn’t work” mean? — rninty
– rninty, Commented Nov 13, 2013 at 0:29
Why did you remove the second example of what you've tried from your question? — Blue Skies
– Blue Skies, Commented Nov 13, 2013 at 0:30
I removed it because it did work and I was alerting it out wrong. — griegs
– griegs, Commented Nov 13, 2013 at 0:35

Alcides Queiroz · Accepted Answer · 2013-11-13 00:27:25Z

3

Based on your phrase "Now I want to check to see whether a room contains a particular entity based on its noun.", so you don't need the entity itself, but to check for its existence:

function check(noun){
  return myRoom.entities.some(function(a){ return a.noun === noun; })
}

var sample = new Entity();
sample.noun = "Test";
sample.title = "Anything";

myRoom.entities.push(sample);

check("Test"); //>>true

answered Nov 13, 2013 at 0:27

Alcides Queiroz

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1 Comment

griegs Over a year ago

Actually that's fits better with my question but both you and @net.uk.sweet have helped solve the issue. and yeah, based on my phrasing this is more correct.

net.uk.sweet · Accepted Answer · 2013-11-13 00:28:20Z

3

JavaScript filter is an array method (see documentation). You should call it on the entities property of your object instead:

var objPillow = myRoom.entities.filter(function (entity) { 
  return entity.noun == "pillow" 
});

edited Nov 13, 2013 at 0:28

answered Nov 13, 2013 at 0:26

net.uk.sweet

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3 Comments

griegs Over a year ago

Erm, yes. Missed that one. Thanks

griegs Over a year ago

Sorry but based on my phrasing of the question the other answer is more correct though i will also be using this answer. thanks again.

net.uk.sweet Over a year ago

That's cool. I went straight to the code, Alcides read and understood the question.

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