I have a zip file and after decoding it I get a byte array now I want to create a FileInputStream object with that byte[] object. I dont want to create a file instead pass data content do FileInputStream. Is there any way ?
following is the code:
byte[] decodedHeaderFileZip = decodeHeaderZipFile(headerExportFile);
FileInputStream fileInputStream = new FileInputStream(decodedHeaderZipFileString);
EDIT: I wanted to build a ZipInputStream object with a FileInputStream.
I have a zip file and after decoding it I get a byte array now I want to create a FileInputStream object with that byte[] object.
But you don't have a file. You have some data in memory. So a FileInputStream is inappropriate - there's no file for it to read from.
If possible, use a ByteArrayInputStream instead:
InputStream input = new ByteArrayInputStream(decodedHeaderFileZip);
Where possible, express your API in terms of InputStream, Reader etc rather than any specific implementation - that allows you to be flexible in which implementation you use. (What I mean is that where possible, make method parameters and return types InputStream rather than FileInputStream - so that callers don't need to provide the specific types.)
If you absolutely have to create a FileInputStream, you'll need to write the data to a file first.
FileInputStream at all, but it's still something to consider.