For in loop and if statement in Python

Question

I'm Trying to figure out how this works. Example One:

n = ["1ab", "2an", "3bca", "4adc"]
l = ["1", "2", "3"]
for m in n:
    if "a" in m:
        for k in l:
            if k in m:
                print k
1
2
3

Now I will try to print last member of n list.

n = ["1ab", "2an", "3bca", "4adc"]
l = ["1", "2", "3"]
for m in n:
    if "a" in m:
        for k in l:
            if not k in m:
                print k

2
3
1
3
1
2
1
2
3

I need to print a list member which does not contain any number listed in l variable but contains "a" in it.

I need to print a list member which does not contain any number listed in l variable but contains "a" in it. — IKA
– IKA, Commented Nov 5, 2013 at 18:52

bukzor · Accepted Answer · 2013-11-05 18:48:09Z

7

Since 4 is not in your list l , you cannot print it.

edited Nov 5, 2013 at 18:48

bukzor

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answered Nov 5, 2013 at 18:44

Srinivas Reddy Thatiparthy

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3 Comments

IKA Over a year ago

Thanks for reply. So how to print it?

Srinivas Reddy Thatiparthy Over a year ago

@iRex it helps a bit more if you say what your are trying to achieve?

IKA Over a year ago

@ Srinivas Reddy Thatiparthy I need to compare if variable n contains any number of indicated in the variable l. Then Print them separately. In second example I need to print ""4adc".

Joucks · Accepted Answer · 2013-11-05 19:08:58Z

2

n = ["1ab", "2an", "3bca", "4adc"]
l = ["1", "2", "3"]
for m in n:
    if "a" in m:
        if not any([k in m for k in l]):
            print m

4adc

answered Nov 5, 2013 at 19:08

Joucks

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Comments

jgranger · Accepted Answer · 2013-11-05 19:12:30Z

1

The answer is in your second to last line. For every loop through n you loop through l and there are three members of n that meet if not k in m: condition. So

Loop 1 prints: 2,3 Loop 2 prints: 1,3 Loop 3 prints: 1,2 Loop 4 prints: 1,2,3

edited Nov 5, 2013 at 19:12

answered Nov 5, 2013 at 19:00

jgranger

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Comments

Jack_of_All_Trades · Accepted Answer · 2013-11-05 19:20:16Z

1

>>> l   
['1', '2', '3']
>>> n   
['1ab', '2an', '3bca', '4adc']
for el in n: 
    if(el[0] not in l):
        print(el)

4adc

Or if you just want to print 4, based on your list sequence:

for el in n: 
    if(el[0] not in l):
        print(el[0])

Now you just added to your question, "but contains "a"", add second iff.

    for el in n: 
        if(el[0] not in l):
            if('a' in el):
                print(el[0],el)

edited Nov 5, 2013 at 19:20

answered Nov 5, 2013 at 19:12

Jack_of_All_Trades

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