Remove array value from object using underscore

Question

I have following object

object = {
  "key1": "value1",
  "key2": "value2",
  "key3": [
     "arrayKey1": "arrayValue1",
     "arrayKey2": "arrayValue2",
     "arrayKey3": "arrayValue3"
   ]
};

When i am using _.omit(object, key3) is working fine. As it is removing the 'key3' correctly. but what if i want to remove the arrayKey2 only and not the whole key3 ?

Your syntax is invalid. Is that an array or an object now?

Bergi
– Bergi

2013-10-14 13:57:31 +00:00
Commented Oct 14, 2013 at 13:57 — Bergi
– Bergi, Commented Oct 14, 2013 at 13:57

idbehold · Accepted Answer · 2013-10-14 19:43:47Z

1

If object.key3 is actually an array:

object.key3 = _.reject(object.key3, function(val, idx){ return idx == 1 })
// Or using the new ES6 syntax:
object.key3 = _.reject(object.key3, (val, idx) => idx == 1)

If object.key3 is an object:

object.key3 = _.omit(object.key3, 'arrayKey2')

edited Oct 14, 2013 at 19:43

answered Oct 14, 2013 at 19:30

idbehold

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