Getting array instead of string

Question

I have tried everything but answer is probably much simple. Variable $data['phone'] is for example 954a23589 and I want only numbers so ill get them.

$phoneW = strval($data['phone']);
preg_match_all('!\d+!', $phoneW, $matches);
print_r(array_values($matches));  echo '<br /><br />';

The output is

Array ( [0] => Array ( [0] => 954 [1] => 23589 ) )

I want everyone of them together as string or int (does not matter).

print_r(implode('', array_values($matches)));

Kuro
– Kuro

2013-10-02 09:04:08 +00:00
Commented Oct 2, 2013 at 9:04 — Kuro
– Kuro, Commented Oct 2, 2013 at 9:04

knittl · Accepted Answer · 2013-10-02 09:05:15Z

7

It's probably easier to replace every non-digit with an empty string:

$number = preg_replace('/\D+/', '', $phoneW);

answered Oct 2, 2013 at 9:05

knittl

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3 Comments

h2ooooooo Over a year ago

..and then use intval($string) or (int)$string to cast it to an integer if needed.

Glavić Over a year ago

@h2ooooooo: you cannot cast phone numbers to int, since phone numbers are normally long numbers and will probably be larger than PHP_INT_MAX.

knittl Over a year ago

@h2ooooooo: and sometimes contain leading zeroes that must not be removed.

C3roe · Accepted Answer · 2013-10-02 09:07:41Z

0

and I want only numbers so ill get them

Why not replace everything that is not a digit with “nothing”?

echo preg_replace('#[^\d]#', '', '954a23589');

answered Oct 2, 2013 at 9:07

C3roe

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