I am trying to get my head around this one.
So here is what I want to do: I have three functions. say, foo,bar and foo_bar
def foo_bar(function):
for i in range(20):
function # execute function
def foo(someargs):
print "hello from foo"
def bar(someargs):
print " hello from bar"
and when i do foo_bar(foo) # how to specify arguments to foo??
I am expecting that I see "hello from foo" 20 times?
But since I am not seeing that.. I clearly dont understand this well enough?
You're not calling the function. You call a function called function by following the name function with brackets (), and inside those brackets you put any arguments you need:
function(function)
I've passed function as a parameter to itself because your foo and bar take arguments, but do nothing with them.
This should do basically what you want:
def foo_bar(function):
for i in range(20):
function(i) # execute function
def foo(someargs):
print "hello from foo"
def bar(someargs):
print " hello from bar"
foo_bar(foo)
foo_bar(bar)
The docs have a section on this here. You most likely want to construct foo_bar as
def foo_bar(function, *func_args):
for i in range(20):
function(func_args)
def foo(a):
print "hello %s"%a
You can then call it as
foo_bar(foo, 'from foo!')
I would make foo_bar return a function that accept the parameters to pass to the internal function:
def foo_bar(fn, n=20):
def _inner(*args, **kwargs):
for i in range(n):
fn(*args, **kwargs)
return _inner
and call it like:
foo_bar(foo)('some_param')
