python static variables and methods

Question

I know there have been several posts about this, but I am still confused. Am trying to use a static variable with initialization, and don't know how to do it. So what I have is a package 'config', which has a module the_config.py. What I would like is for this to be something like

# the_config.py

import yaml

user_settings=None

def initialize(user_settings_file)

  with open(user_settings_file) as yaml_handle:
     user_settings = yaml.safe_load(user_settings_file)

Then there would be a calling module as pipeline.py

#pipeline.py

import config.the_config as my_config

def main(argv):

    ...
    my_config.intialize(user_settings_file)
    print my_config.user_settings['Output_Dir']

But this doesn't work. How should I be doing this please?

Thanks in advance.

user4815162342 · Accepted Answer · 2013-09-23 17:26:40Z

3

When you assign to user_settings, it is automatically treated as a local variable in the initialize function. To tell Python that the assignment is intended to change the global variable instead, you need to write

global user_settings

at the beginning of initialize.

answered Sep 23, 2013 at 17:26

user4815162342

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6502 · Accepted Answer · 2013-09-23 17:35:04Z

0

In Python any variable that is assigned in the body of a function is considered a local variable, unless it's has been explicitly declared differently with either global or nonlocal declarations.

Python considers also assignment any "augmented-assignment" operator like += or /=.

The mandatory declaration of global that are modified is a (little) price to pay to the fact that in Python there is no need to declare variables.

It's also assumed that your code doesn't rely too much on mutating state in that is kept global variables so if your code requires a lot of global declarations then there's probably something wrong.

answered Sep 23, 2013 at 17:35

6502

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1 Comment

user2689782 Over a year ago

I just want to do this for a few things - like config and log settings. So initialize them once, and then use them throughout all the classes

oleg · Accepted Answer · 2013-09-23 17:58:53Z

I can propose You some way to solve this.

First of all the root of your problem is creation of new local variable in your initialize function

user_settings = yaml.safe_load(user_settings_file)

As soon as there is equal sign right to variable name python create new variable in corresponding scope (in this case local for initialize function

to avoid this one can use following:

use global declaration

def initialize(user_settings_file)
    global user_settings # here it is
    with open(user_settings_file) as yaml_handle:
        user_settings = yaml.safe_load(user_settings_file)

modify existing variable but not create new one

user_settings = {}
def initialize(user_settings_file)
    with open(user_settings_file) as yaml_handle:
        user_settings.update(yaml.safe_load(user_settings_file)) # here we modify existing user_settings

operate with module attribute (this one is quite tricky)

user_settings = {}
def initialize(user_settings_file)
    with open(user_settings_file) as yaml_handle:
        import the_config
        the_config.user_settings = yaml.safe_load(user_settings_file)

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