PHP - undefined offset: 0

Question

print_r($p->attachments) produces:

Array
(
    [0] => stdClass Object
        (
            [id] => ...
            [url] => http://...png
            [slug] => ...
            [title] => ...
            [description] => ...
            [caption] => ...
            [parent] => ...
            [mime_type] => image/png
            [images] => ...
                (
                )
        )
)

I wish to access the value in the url field

print_r($p->attachments[0]->url) retrieves the url, but also produces: Undefined offset: 0

Now I can supress the error by calling print_r(@$p->attachments[0]->url), but is there a proper way of fixing this?

I am not able to modify the $p object.

Edit:

As suggested, here is response from Var_dump($p->attachments)

 array(1) {
  [0]=>
  object(stdClass)#322 (9) {
    ["id"]=>
    int(1814)
    ["url"]=>
    string(76) "..."
    ["slug"]=>
    string(34) "..."
    ["title"]=>
    string(34) "..."
    ["description"]=>
    string(0) ""
    ["caption"]=>
    string(53) "..."
    ["parent"]=>
    int(1811)
    ["mime_type"]=>
    string(9) "image/png"
    ["images"]=>
    array(0) {
    }
  }
}

@DontVoteMeDown I would if I could. That buries the problem rather than solves it. — George Brighton
– George Brighton, Commented Sep 18, 2013 at 19:17
it seems that $p->attachments[0] is not defined every time you try to access it. You can suppress errors if you do: if(isset($p->attachments[0])) { .... } before trying to access it. — steven
– steven, Commented Sep 18, 2013 at 19:17
From the code you've given, there's no reason for the error. I image $p->attachments is sometimes empty, in which case you need to check for this before accessing its first element. — George Brighton
– George Brighton, Commented Sep 18, 2013 at 19:19

Suvash sarker · Accepted Answer · 2013-09-18 19:28:13Z

15

You can use isset() for check the array:

if(isset($p->attachments[0])){
    echo $p->attachments[0]->url;
}
else {
  //some error?
}

Or if you know that you are only going to be checking index 0 then you can do this way

$array = $array + array(null);

So if the original $array[0] was unset, now it is null

answered Sep 18, 2013 at 19:28

Suvash sarker

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Comments

halfik · Accepted Answer · 2013-09-18 19:42:04Z

0

dunno why it returns you a value and informs you that there is undefined offset 0. strange.

can you check this (since attachments is an array you should do this that way):

if ( count($p->attachments) > 0 ){ 
   foreach ($p->attachments AS $att){
    //do the stuff if attachement 
   }
}

answered Sep 18, 2013 at 19:42

halfik

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