i Want to validate a text field in keyup event .
in the field it should accept money type decimal like
(12.23) (.23) (0.26) (5.09) (6.00)
if i enter some wrong value then it should return to the previous value and remove the wrong one
3
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Thats your requirement, what have you tried so far? I would be easy for us to point out the mistake if you show us the code.Praveen– Praveen2013-08-28 06:20:34 +00:00Commented Aug 28, 2013 at 6:20
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@abiansh what does it mean when you say "it should return to the previous value"zzlalani– zzlalani2013-08-28 06:33:03 +00:00Commented Aug 28, 2013 at 6:33
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var theEvent = evt || window.event; var key = theEvent.keyCode || theEvent.which; key = String.fromCharCode(key); var regex = /^(\d{0,2})(\.\d{2})$/; // number with 2 decimal places if (!regex.test(key)) { theEvent.returnValue = false; //--- this prevents the character from being displayed if (theEvent.preventDefault) theEvent.preventDefault(); }abiansh– abiansh2013-08-29 05:08:49 +00:00Commented Aug 29, 2013 at 5:08
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4 Answers
I think something like this might be your best bet
var isValidCurrency = function(str) {
var num = parseFloat(str);
return !Number.isNaN(num) && num.toFixed(2).toString() === str;
};
Some tests
isValidCurrency("1234.56"); // true
isValidCurrency("1234.565"); // false
isValidCurrency("1234"); // false
isValidCurrency("foo"); // false
4 Comments
ryanVincent
Doesn't work for the edge case "00.00"
Mulan
I would argue that more than one leading zero is not valid.
Mulan
@T.G, "123foo" is not a valid currency.
isValidCurrency("123foo") returns false which is appropriate in this case.Mulan
@T.G if you want, you can delete your comments and I'll delete mine to avoid confusion for other users.
You can use following Regex
val = "2.13"
if (!val.match(/^(\d{0,2})(\.\d{2})$/)) {
alert("wrong");
} else {
alert("right");
}
EDIT
Please note that if the numbers preceding dot (.) has limit of length to two then the code valid code is
^(\d{0,2})(\.\d{2})$
else if there is no limit then just remove the 2 from the code i.e.
^(\d{0,})(\.\d{2})$
Comments
Try this:
function evMoneyFormat(evt) {
//--- only accepts accepts number and 2 decimal place value
var theEvent = evt || window.event;
var key = theEvent.keyCode || theEvent.which;
key = String.fromCharCode(key);
var regex = /^[0-9]{1,14}\.[0-9]{0,2}$/; // number with 2 decimal places
if (!regex.test(key)) {
theEvent.returnValue = false;
//--- this prevents the character from being displayed
if (theEvent.preventDefault) theEvent.preventDefault();
}
}
The control:
<input type='text' onkeyup='evMoneyFormat( e );'>
Comments
Try following code
function validateDecimal(num){
var dotPosition=num.indexOf(".");
if(dotPosition=="-1"){
document.getElementById('cost').value= num+".00"
}
}
And in html
<input type="text" id='cost' onkeyup="validateDecimal(this.value)" />
1 Comment
Faisal Sayed
You are multiplying number by hundred? need to add
. before 00.