I'm trying:
String string = "123456";
if(string.startsWith("[0-9]") && string.endsWith("[0-9]")){
//code
}
And the if clause is never called.
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5What led you to believe it's a regex argument?Dave Newton– Dave Newton2013-08-02 14:36:39 +00:00Commented Aug 2, 2013 at 14:36
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Where is the variable name?Rohit Jain– Rohit Jain2013-08-02 14:37:04 +00:00Commented Aug 2, 2013 at 14:37
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1Is it just me or is there no question in the post?Akunosh– Akunosh2013-08-02 14:39:04 +00:00Commented Aug 2, 2013 at 14:39
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1We have assumed the missing last word is: "Why?"arjacsoh– arjacsoh2013-08-02 14:40:15 +00:00Commented Aug 2, 2013 at 14:40
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5 Answers
Don't use a regex:
Character.isDigit(string.charAt(0)) &&
Character.isDigit(string.charAt(string.length()-1))
(see Character.isDigit())
3 Comments
Paul Vargas
I think that this is the more faster way.
dic19
I agree, no regex needed.
arshajii
@MattSmith Are you sure it's from this line? There are no cases where this should cause an
IllegalStateException. Try checking the surrounding code.The methods startsWith() and endsWith() in class String accept only String, not a regex.
1 Comment
Leigh
Very true, but as it stands this is more of comment than an answer. How would you suggest they "...[check] if a string starts and ends with number characters."?
You can use the matches method on String thusly:
public static void main(String[] args) throws Exception {
System.out.println("123456".matches("^\\d.*?\\d$"));
System.out.println("123456A".matches("^\\d.*?\\d$"));
System.out.println("A123456".matches("^\\d.*?\\d$"));
System.out.println("A123456A".matches("^\\d.*?\\d$"));
}
Output:
true
false
false
false
1 Comment
Thank you for the solution, I want to use the same concept in javascript, however when I use
^\\d.*?\\d$ for a string, it does not work. For string 3rd it should give false and for strings 3 or 3(white spaces) the output should be true. Any guidance would be much appreciated.You can use:
String string = "123test123";
if(string.matches("\\d.*\\d"))
{
// ...
}
1 Comment
arshajii
@ProgramFOX You actually don't need the anchors with
matches().Please follow the code snippet.
String variableString = "012testString";
Character.isDigit(string.charAt(0)) && variableString.Any(c => char.IsUpper(c));
