PHP include not executing code

Question

I have an include in the head of my php file:

include 'scripts/tracking_code.php';

In there, I run a basic test with if/else and echo some basic text.

Problem is that nothing is getting printed to screen.

I then just tried to print something a little more basic... The tracking_code.php now simply includes this:

echo "<!-- This is the file -->";

Still nothing?

I know the include is getting included because when I turn E_ALL error reporting, the $_GET[] call throws a "Notice: Undefined index:"

Here is my original code (before simply replacing with "echo" (as above))

<?php

$trackingid = $_GET['trackingid'];

if ( !empty( $trackingid ) ) {
    echo "<!-- trackingid: $trackingid -->";
} else { 
    echo "<!-- trackingid is empty -->";
}
?>

Yet nothing is ever printed?

What am I missing?

Are you sure you're looking at the source and not the HTML output (which would render HTML comments invisible)? — Andrew Cheong
– Andrew Cheong, Commented Jul 22, 2013 at 1:30
Definitely looking at the source ... I am printing before any HTML and there is nothing appearing — php-b-grader
– php-b-grader, Commented Jul 22, 2013 at 1:38
 signifies a comment in HTML and you'll not see it on the screen. — DevlshOne
– DevlshOne, Commented Jul 22, 2013 at 1:39
Yes: Right click -> View Source - It is a comment because I don't want it printing on screen for consumers to see — php-b-grader
– php-b-grader, Commented Jul 22, 2013 at 1:43
It would appear that comments do not print in the source before the <DOCTYPE> tag... Would this be correct? — php-b-grader
– php-b-grader, Commented Jul 22, 2013 at 1:59

Mike 'Pomax' Kamermans · Accepted Answer · 2013-07-22 05:08:19Z

3

Is your tracking script echo ""; or is it

<?php
  echo "<!-- This is the file -->";
?>

Because without the php tags, there's a good chance that your require call actually makes PHP go "this is not actually a PHP file and as such I cannot require it" but with the error/warning repressed due to whatever error reporting settings are active when you run the code.

answered Jul 22, 2013 at 5:08

Mike 'Pomax' Kamermans

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