I was under the impression that a calling script can access the namespace of the called script. Following is a code section from my calling script:
x= 'python precision.py'
args=shlex.split(x)
print args
p=subprocess.Popen(args)
p.wait()
result.write("\tprecision = "+str(precision)+", recall = ")
where "precision" is a variable in the called script "precision.py". But this gives a NameError. How could i fix this?
You can't access this. By the time you have arrived in the last line of your script, the called script has finished executing. Therefore its variables don't exist any more. You need to send this data to the calling script in some other way (such as the called script printing it on the standard output and the calling script getting it from there).
Even if it hadn't finished executing, I don't think you could access its variables. In other words, your impression is wrong :-)
subprocess.Popen() allows you to run a command and read from its standard output and/or write to its standard input. It doesn't make much sense to popen a process and then wait for it to finish without communicating with it. That's pretty much like os.system()
If you want a variable in precision.py you do something like the following:
import precision
print "precision variable value =", precision.precision
of course, importing means executing any statements not inside classes or def's
