The JS function is
function func(arg){
alert(arg);
}
When I do
echo "<div onclick=\"func($arg)\">Text</div>";
in php, it doesnt work but when I do
echo "<div onclick=\"func()\">Text</div>";
it works and an alert with undefined text pops up.
How do I pass argument?
You need to quote the arguments. e.g.
<?php
$foo = 'bar';
?>
echo "function($foo) { ... }";
is going to produce the code
function(bar) { ... }
where bar will be interpreted as an undefined variable.
Safest method is to output your PHP variables via json_encode(), to guarantee you're producing syntactically valid javascript. e.g.
echo 'function(' . json_encode($foo) . ') { ... }';
which would produce (in this case)
function ('bar') { ... }
You need to wrap $arg in quotes. Example:
echo "<div onclick=\"func('$arg')\">Text</div>";
(using single quotes around arg as you're using double quotes for the string)
You can do like this (if $args exists of course)
echo '<div onclick="func('.$arg.')">Text</div>';
$arga PHP variable?