Write multiple values into text file in Python?

Question

I have created a set of 6 random integers and I wish to write 500 of them into a text file so it looks like this inside the text file:

x, x, xx, x, xx, x \n x, x, x, xx, x, x ....etc

(where x is an integer)

from random import shuffle, randint

def rn():
    return randint(1,49);

print "Random numbers are: " , rn(), rn(), rn(), rn(), rn(), rn()

There must be an easier way than pasting the last line 500 times?

EDIT: Why all the down votes? I'm sorry if this is a basic question for you guys but for someone learning python it's not.

Regarding the downvotes, I'd image people will recommend you complete a basic Python tutorial first: codecademy.com/courses/… — Jace Browning
– Jace Browning, Commented Jul 1, 2013 at 17:28
Downvoted because solutions to your problem (e.g. Loops) are found in the most basic of programming tutorials; and this site is not meant to teach you the fundamentals of programming. It is expected that you do some work on your own (like reading a python tutorial) before asking a question. — l4mpi
– l4mpi, Commented Jul 1, 2013 at 17:28
Ok, thank you for your help. I will do that in future, regards. — user2519572
– user2519572, Commented Jul 1, 2013 at 17:38

jh314 · Accepted Answer · 2013-07-01 17:16:01Z

3

How about this:

print "Random numbers are: "
for _ in xrange(500):
    print rn(), rn(), rn(), rn(), rn(), rn()

If you want to write to text file:

with open('Output.txt', 'w') as f:
    f.write("Random numbers are: \n")
    for _ in xrange(500):
        f.write("%s,%s,%s,%s,%s,%s\n" % (rn(), rn(), rn(), rn(), rn(), rn()))

edited Jul 1, 2013 at 17:16

answered Jul 1, 2013 at 17:08

jh314

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2 Comments

user2519572 Over a year ago

That's great, but I want to print them into a text file, how would I do that? e.g ext_file = open("Output.txt", "w") text_file.write("Purchase Amount: " 'rn(), rn(), rn(), rn(), rn(), rn()') text_file.close()

user2519572 Over a year ago

Could you tell me how to sort it by ascending number? I tried the sort() feature but no luck

Ignacio Vazquez-Abrams · Accepted Answer · 2013-07-01 17:07:50Z

0

Iterate over a sufficiently-large generator.

for linenum in xrange(500):
   ...

answered Jul 1, 2013 at 17:07

Ignacio Vazquez-Abrams

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Comments

number5 · Accepted Answer · 2013-07-01 17:09:27Z

0

Surely we have simple way :)

from random import randint

def rn():
    return randint(1, 49)

for i in xrange(500):
    print rn()

answered Jul 1, 2013 at 17:09

number5

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Comments

Jon Clements · Accepted Answer · 2013-07-01 17:10:49Z

0

Could use the following:

from random import randint
from itertools import islice

rand_ints = iter(lambda: str(randint(1, 49)), '')
print 'Random numbers are: ' + ' '.join(islice(rand_ints, 500))

And dump those to a file as such:

with open('output', 'w') as fout:
    for i in xrange(500): # do 500 rows
        print >> fout, 'Random numbers are: ' + ' '.join(islice(rand_ints, 6)) # of 6 each

answered Jul 1, 2013 at 17:10

Jon Clements

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Comments

Ashwini Chaudhary · Accepted Answer · 2013-07-01 17:20:56Z

0

Use a for-loop:

from random import shuffle, randint

def rn():
    return randint(1,49);

with open('out.txt', 'w') as f:
    for _ in xrange(500):
        f.write(str(rn()) + '\n')

If you want 6 of them on each line:

with open('out.txt', 'w') as f:
    for _ in xrange(500):
        strs = "Purchase Amount: {}\n".format(" ".join(str(rn()) 
                                                          for _ in xrange(6)))
        f.write(strs)

edited Jul 1, 2013 at 17:20

answered Jul 1, 2013 at 17:08

Ashwini Chaudhary

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