Shell script to check one script output and then run second script

Question

I want a script to run a main.ksh to run both one.ksh and second.ksh only if output of one.ksh matches "1". So if the output is anything other than "1" then second.ksh shouyld not run.

 cat one.ksh
 #!/usr/bin/ksh
 echo "1"

cat second.ksh
#!/usr/bin/ksh

echo "2"

I did this:

#!/usr/bin/ksh

ksh .ksh > one.txt

file="one.txt"

while read line
do

if [ $line -eq 2 ] ;then
ksh second.ksh
else
echo "one.ksh is no good"
fi
done <"$file"

Any better way ro this is good?

And ... you don't know how to do it?

martin clayton
– martin clayton

2013-06-04 23:14:10 +00:00
Commented Jun 4, 2013 at 23:14 — martin clayton
– martin clayton, Commented Jun 4, 2013 at 23:14

that other guy · Accepted Answer · 2013-06-04 23:41:10Z

3

Instead of echo 1 to proceed from the first script, you should use exit 0. If it shouldn't proceed, exit 1.

This is the standard way of signaling success and failure in Unix.

Once you do this, you can use any of:

first.ksh && second.ksh

or

if first.ksh
then
    second.ksh
fi

or

set -e  # Automatically exit script if a command fails
first.ksh
second.ksh

answered Jun 4, 2013 at 23:41

that other guy

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Comments

Ochi · Accepted Answer · 2013-06-04 23:21:13Z

1

out=`one.ksh`

if [ "x$out" == "x1" ]; then
    second.ksh
fi

answered Jun 4, 2013 at 23:21

Ochi

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1 Comment

glenn jackman Over a year ago

You can simplify a bit: [[ "$(one.ksh)" == "1" ]] && second.ksh

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