Converting a numpy string array to integers in base-16

Question

I am looking for a way to convert an array of strings in numpy to the integers they represent in hexadecimal. So in other words, the array version of:

int("f040", 16)

I can convert a string array to integers base-10 by calling arr.astype(numpy.int32), but I can't see any obvious way to convert them base-16. Does anyone know of a way to do this?

Michel Keijzers · Accepted Answer · 2013-05-02 13:50:25Z

3

ar = ['f040', 'deadbeaf'] 
int_array = [int(a, 16) for a in ar]
print int_array

output:

[61504, 3735928495L]

answered May 2, 2013 at 13:50

Michel Keijzers

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3 Comments

user206545 Over a year ago

You don't need to prefix a with '0x'

dpitch40 Over a year ago

I am aware that list comprehensions can solve the problem, I was wondering if there was a "fast" method in numpy itself analogous to astype.

Michel Keijzers Over a year ago

@dpitch40 Probably there is not a fast answer, although the list comprehension is only a very short line. Or do you mean performance wise? (numpy is generally about 10 times faster than Python functions).

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