How to get property from dynamic JObject programmatically

Question

I'm parsing a JSON string using the NewtonSoft JObject. How can I get values from a dynamic object programmatically? I want to simplify the code to not repeat myself for every object.

public ExampleObject GetExampleObject(string jsonString)
{
ExampleObject returnObject = new ExampleObject();
dynamic dynamicResult = JObject.Parse(jsonString);
if (!ReferenceEquals(dynamicResult.album, null))
   {
       //code block to extract to another method if possible
       returnObject.Id = dynamicResult.album.id; 
       returnObject.Name = dynamicResult.album.name;
       returnObject.Description = dynamicResult.albumsdescription;
       //etc..
   }
else if(!ReferenceEquals(dynamicResult.photo, null))
   {
       //duplicated here
       returnObject.Id = dynamicResult.photo.id;
       returnObject.Name = dynamicResult.photo.name;
       returnObject.Description = dynamicResult.photo.description;
       //etc..
   }
else if..
//etc..

return returnObject;
}

Is there any way I can extract the code blocks in the "if" statements to a separate method e.g:

private void ExampleObject GetExampleObject([string of desired type goes here? album/photo/etc])
{
  ExampleObject returnObject = new ExampleObject();
  returnObject.Id = dynamicResult.[something goes here?].id;
  returnObject.Name = dynamicResult.[something goes here?].name;
  //etc..
  return returnObject;
}

Is it even possible since we can't use reflection for dynamic objects. Or am I even using the JObject correctly?

Thanks.

Is the jsonString a string that is under your control? Or are you receiving this from another party and you need to communicate with it? — MichaelD
– MichaelD, Commented Apr 19, 2013 at 5:59
@MichaelD it's from another party. I'm just receiving and parsing. — dcdroid
– dcdroid, Commented Apr 19, 2013 at 13:05
More answers see deserializing JSON to .net object using NewtonSoft (or linq to json maybe?) — Michael Freidgeim
– Michael Freidgeim, Commented Jul 22, 2016 at 7:55

Connie Hilarides · Accepted Answer · 2013-04-30 15:44:21Z

59

Assuming you're using the Newtonsoft.Json.Linq.JObject, you don't need to use dynamic. The JObject class can take a string indexer, just like a dictionary:

JObject myResult = GetMyResult();
returnObject.Id = myResult["string here"]["id"];

Hope this helps!

answered Apr 30, 2013 at 15:44

Connie Hilarides

1,74515 silver badges13 bronze badges

Sign up to request clarification or add additional context in comments.

5 Comments

joelforsyth Over a year ago

What goes in ["string here"]? Wouldn't "id" just return the value of ID in the object?

mardok Over a year ago

Is this case insensitive?

Aaron Over a year ago

@joelforsyth, yes you might do, depending on the object structure, e.g. returnObject.Id = (int)myResult["id"];

Iain Over a year ago

@mardok No, unfortunately it is case sensitive and so it may or may not work depending on the JsonSerializer settings that were used to serialize the object.

John Foll Over a year ago

Wow! Thanks for the tip! I was trying to use GetProperty. For me I needed to apply it with a cast similar to this (but different type): String MyProperty1Value = (String)((Newtonsoft.Json.Linq.JObject)This.Tag)["MyProperty1"]; This just for an example, not my actual code. I was using a lambda fct.

Ziad Akiki · Accepted Answer · 2019-01-23 15:53:45Z

7

Another way of targeting this is by using SelectToken (Assuming that you're using Newtonsoft.Json):

JObject json = GetResponse();
var name = json.SelectToken("items[0].name");

For a full documentation: https://www.newtonsoft.com/json/help/html/SelectToken.htm

answered Jan 23, 2019 at 15:53

Ziad Akiki

2,7102 gold badges29 silver badges46 bronze badges

Comments

Hamit YILDIRIM · Accepted Answer · 2019-02-24 10:52:59Z

0

with dynamic keyword like below:

private static JsonSerializerSettings jsonSettings;

private static T Deserialize<T>(string jsonData)
{
   return JsonConvert.DeserializeObject<T>(jsonData, jsonSettings);
}

//if you know what will return

var jresponse = Deserialize<SearchedData>(testJsonString);

//if you know return object type you should sign it with json attributes like

[JsonObject(MemberSerialization = MemberSerialization.OptIn)]
public class SearchedData
{
    [JsonProperty(PropertyName = "Currency")]
    public string Currency { get; set; }
    [JsonProperty(PropertyName = "Routes")]
    public List<List<Route>> Routes { get; set; }
}

// if you don't know the return type use dynamic as generic type

var jresponse = Deserialize<dynamic>(testJsonString);

edited Feb 24, 2019 at 10:52

answered Apr 25, 2017 at 15:22

Hamit YILDIRIM

4,5991 gold badge37 silver badges37 bronze badges

2 Comments

joedotnot Over a year ago

what dynamic keyword, you did not even write dynamic in your response?

Hamit YILDIRIM Over a year ago

joedotnot i have corrected my answer use like that, if you face any problem please write again

Collectives™ on Stack Overflow

How to get property from dynamic JObject programmatically

3 Answers 3

5 Comments

Comments

2 Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

5 Comments

Comments

2 Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related