How to assign pointer to 2D array in struct in C?

Question

I am having a problem with assigning a pointer to a 2d array located in a struct in C. The code runs but I am getting a compilation error and can not understand how to get rid of it.

First, the struct

typedef struct{
  double (*cases)[9];
} myStruct;

I then declare a struct of type myStryct and an array in my main program and try to set the pointer in my struct to point at this array:

 myStruct a;
 double myArray[5][9] = {
   {0, 1, 2, 3, 4, 5, 6, 7, 8},
   {0, 1, 2, 3, 4, 5, 6, 7, 8},
   {0, 1, 2, 3, 4, 5, 6, 7, 8},
   {0, 1, 2, 3, 4, 5, 6, 7, 8},
   {0, 1, 2, 3, 4, 5, 6, 7, 8},
 }
 a.cases = &myArray;

The program run fines and I can access elements via the pointer but I get a compilation error: Warning: assignment from compatible pointer type. What is the problem here?

Did you post the actual code ? Why is myArray missing a type ? — Paul R
– Paul R, Commented Apr 11, 2013 at 9:41
This may help you - stackoverflow.com/questions/15207888/… — AB Bolim
– AB Bolim, Commented Apr 11, 2013 at 9:42
Also refer this one - stackoverflow.com/questions/6770507/… — AB Bolim
– AB Bolim, Commented Apr 11, 2013 at 9:43

BLUEPIXY · Accepted Answer · 2013-04-11 09:51:37Z

1

myStruct a;
double myArray[5][9] = {
   {0, 1, 2, 3, 4, 5, 6, 7, 8},
   {0, 1, 2, 3, 4, 5, 6, 7, 8},
   {0, 1, 2, 3, 4, 5, 6, 7, 8},
   {0, 1, 2, 3, 4, 5, 6, 7, 8},
   {0, 1, 2, 3, 4, 5, 6, 7, 8},
};
a.cases = &myArray[0];

answered Apr 11, 2013 at 9:51

BLUEPIXY

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Comments

MahaSwetha · Accepted Answer · 2013-06-11 09:55:16Z

0

problem:

void allocate(int ** universe,int n) // to assign pointer "a"  a nXn matrix //
{ 
   universe=(int **) calloc(n,sizeof(int *));
   cout<<"work3";
   int l;
   for(l=0;l<n;l++)
   universe[l]=(int *)calloc(n,sizeof(int));
}

edited Jun 11, 2013 at 9:55

MahaSwetha

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answered Jun 11, 2013 at 9:32

Parikshit

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