Populating Field from Multiple Input Fields?

Question

I'm trying to populate a field with Street Address, City, State, and Zip but right now when I enter data into each field it replaces the last one.

$("#trainer_address").keyup( function () {
        $('#location').val($(this).val());
    });

    $("#trainer_city").keyup( function () {
        $('#location').val($(this).val());
    });

    $("#trainer_state").keyup( function () {
        $('#location').val($(this).val());
    });

    $("#trainer_zip").keyup( function () {
        $('#location').val($(this).val());
    });

How do I get it to keep the previous value, and then add the next so I can end up with something like 402 StreetAddress City State, 12345?

It's interesting. What happens if you then return back to the first field? Should it append one more time? — dfsq
– dfsq, Commented Mar 13, 2013 at 5:26

dfsq · Accepted Answer · 2013-03-13 06:15:33Z

1

This script will do it:

var $loc = $('#location'),
    address = [],

getAddress = function() {
    var str = address.slice(0, 3).join(' ') + ', ' + (address[3] || '');
    return str.replace(/\s+/g, ' ').replace(/,\s$/, '');
}

$("#trainer_address, #trainer_city, #trainer_state, #trainer_zip").on({
    focus: function() {
        $loc.val(getAddress());
    },
    keyup: function() {
        address[$(this).index()] = $(this).val();
        $(this).trigger('focus');
    }
});

http://jsfiddle.net/J6G9f/1/

Script also correctly handles removing parts of the address and it automatically updates the result.

edited Mar 13, 2013 at 6:15

answered Mar 13, 2013 at 5:38

dfsq

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Comments

bipen · Accepted Answer · 2013-03-13 05:19:50Z

0

concatenate the old val with new val using + operator...and you can avoid multiple keyup function using multiple selector....

try this

$("#trainer_address,#trainer_city,#trainer_state,#trainer_zip").keyup( function () {
  var location=$('#location').val();
  $('#location').val(location + $(this).val());
});

answered Mar 13, 2013 at 5:19

bipen

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1 Comment

Joe Bobby Over a year ago

for some reason, typing in street i end up with streetstreetstreet

elclanrs · Accepted Answer · 2013-03-13 05:21:41Z

0

You can use the native value like this:

$('#location')[0].value += this.value;

answered Mar 13, 2013 at 5:21

elclanrs

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2 Comments

Joe Bobby Over a year ago

how do I add this solution?

elclanrs Over a year ago

You just have to replace the line where you set the value.

Jace · Accepted Answer · 2013-03-13 05:43:59Z

0

That's because you're overwriting it. Try concatenating:

$('#location').val($('#location').val() + $(this).val());

For example, change this:

$("#trainer_zip").keyup( function () {
    $('#location').val($(this).val());
});

to this:

$("#trainer_zip").keyup( function () {
    $('#location').val($('#location').val() + $(this).val());
});

Do that for each keyup() event function

edited Mar 13, 2013 at 5:43

answered Mar 13, 2013 at 5:19

Jace

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1 Comment

Joe Bobby Over a year ago

confused on how to implement this solution

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