Java array, NullPointerException?

Question

I declared two cards:

Card card1 = new Card('3', Card.Suit.clubs);
Card card2 = new Card('T', Card.Suit.diamonds);

This works:

Hand hand1 = new Hand();

hand1.takeCard(card1);

But why does this not work? It gives me a NullPointerException on second line:

Hand[] hand = new Hand[2];

hand[0].takeCard(card2);

Amarnath · Accepted Answer · 2013-03-02 03:01:03Z

10

You are declaring an array of 2 hands. This is just setting up the array. You then need to instantiate the hand objects inside the array.

Say

hand[0] = new Hand(); 
hand[1] = new Hand();

Amarnath

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answered Mar 2, 2013 at 3:00

Daniel Williams

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Comments

shounak · Accepted Answer · 2013-03-02 03:59:41Z

-1

I think you need to go though this... I will clear your concepts... Please refer Java tutorials as and when possible.. its helpful

answered Mar 2, 2013 at 3:59

shounak

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