Making a decryption program in python

Question

So a little while ago I asked for some help with an encryption program,
And you guys were amazing and came up with the solution.
So I come to you again in search of help for the equivalent decryption program. The code I have got so far is like this:

whinger = 0
bewds = raw_input ('Please enter the encrypted message: ')
bewds = bewds.replace(' ', ', ')
warble = [bewds]
print warble
wetler = len(warble)
warble.reverse();
while whinger < wetler:
    print chr(warble[whinger]),
    whinger += 1

But when I input
101 103 97 115 115 101 109
it comes up with the error that the input is not an integer.
What I need is when I enter the numbers it turns them into a list of integers.
But I don't want to have to input all the numbers separately.

Thanks in advance for your help :P

jfs · Accepted Answer · 2013-02-05 09:19:55Z

2

To convert input string into a list of integers:

numbers = [int(s) for s in "101 103 97 115 115 101 109".split()]

answered Feb 5, 2013 at 9:19

jfs

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3 Comments

aychedee Over a year ago

He is also adding ','. So he might need to do a split(', ') or just stop adding commas.

jfs Over a year ago

@aychedee: split(", ") won't work if there is no space after comma and it won't split integers separated by whitespace. @martineau's answer with replace(",", " ").split() could be used to support both spaces and commas. Though I'd limit valid input only to spaces for simplicity.

aychedee Over a year ago

Yeah, but he was explicitly replacing spaces with , . (comma, space) So :-P

martineau · Accepted Answer · 2013-02-05 09:58:56Z

1

Here's almost the simplest way I can think of to do it:

s = '101 103 97 115 115 101 109'
numbers = []
for number_str in s.replace(',', ' ').split():
    numbers.append(int(number_str))

It will allow the numbers to be separated with commas and/or one or more space characters. If you only want to allow spaces, leave the ".replace(',', ' ')" out.

edited Feb 5, 2013 at 9:58

answered Feb 5, 2013 at 9:44

martineau

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Comments

Community · Accepted Answer · 2017-05-23 11:48:50Z

0

Your problem is, that raw_input returns a string to you. So you have two options.

1, Use regular expression library re. E.G.:

import re
bewds = raw_input ('Please enter the encrypted message: ')
some_list = []
for find in re.finditer("\d+", bewds):
    some_list.append(find.group(0))

2, Or you can use split method as described in the most voted answer to this question: sscanf in Python

edited May 23, 2017 at 11:48

CommunityBot

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answered Feb 5, 2013 at 9:21

Jendas

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2 Comments

Jendas Over a year ago

Sure, that's why I have mentioned it :-) But asking guy is obviously new in python so a little more options, how to do that, won't do any harm :-)

martineau Over a year ago

IMHO, someone new should be shown the simplest way(s) to do it first.

Community · Accepted Answer · 2017-05-23 12:12:30Z

0

You could also use map

numbers = map(int, '101 103 97 115 115 101 109'.split())

This returns a list in Python 2, but a map object in Python 3, which you might want to convert into a list.

numbers = list(map(int, '101 103 97 115 115 101 109'.split()))

This does exactly the same as J. F. Sebastian's answer.

edited May 23, 2017 at 12:12

CommunityBot

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answered Feb 5, 2013 at 9:25

Volatility

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