getting correct path of a folder in python

Question

I have a directory structure as below

/home/damon/dev/python/misc/path/
                                /project/mycode.py
                                /app/templates/

I need to get the absolute path of the templates folder from mycode.py

I tried to write mycode.py as

import os

if __name__=='__main__':
    PRJ_FLDR=os.path.dirname(os.path.abspath(__file__))
    print 'PRJ_FLDR=',PRJ_FLDR
    apptemplates = os.path.join(PRJ_FLDR,'../app/templates')
    print 'apptemplates=',apptemplates

I expected the apptemplates to be

/home/damon/dev/python/misc/path/app/templates

but I am getting

/home/damon/dev/python/misc/path/project/../app/templates

How do I get the correct path?

Colonel Panic · Accepted Answer · 2013-01-20 16:39:34Z

5

That path is correct, try it. But if you want to remove the redundant 'project/../' section for clarity, use os.path.normpath

os.path.normpath(path)

Normalize a pathname. This collapses redundant separators and up-level references so that A//B, A/B/, A/./B and A/foo/../B all become A/B.

http://docs.python.org/2/library/os.path.html#os.path.normpath

edited Jan 20, 2013 at 16:39

answered Jan 20, 2013 at 12:41

Colonel Panic

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Comments

Rubens · Accepted Answer · 2013-01-20 16:45:55Z

1

Is this what you want?

import os

if __name__=='__main__':
    PRJ_FLDR=os.path.dirname(os.path.abspath(__file__))
    print 'PRJ_FLDR=',PRJ_FLDR
    apptemplates = os.path.abspath(os.path.join(PRJ_FLDR, '../app/templates'))
    print 'apptemplates=',apptemplates

Considering the comments, I made the proper edit.

edited Jan 20, 2013 at 16:45

answered Jan 20, 2013 at 12:28

Rubens

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3 Comments

damon Over a year ago

this would yield home/damon/dev/python/misc/path/project/app/templates which is wrong..it should be home/damon/dev/python/misc/path/app/templates

hughdbrown Over a year ago

I'd recommend joining the paths and then normalizing: os.path.abspath(os.path.join(PRJ_FLDR, '../app/templates'))

Colonel Panic Over a year ago

Hugh is right, you need to do the join first then the abspath, otherwise the code is wrong. (Although it happens it will be correct when the working directory is PRJ_FLDR).

damon · Accepted Answer · 2013-01-20 12:37:48Z

0

I tried this ,and it seems to work

parentpath=os.path.abspath(os.path.join(os.path.dirname(__file__),".."))
apptemplates=os.path.join(parentpath,'app/templates')

answered Jan 20, 2013 at 12:37

damon

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Comments

xmonk · Accepted Answer · 2013-01-20 12:46:20Z

0

This works:

apptemplates = os.path.join(os.path.split(PRJ_FLDR)[0], "app/templates")

answered Jan 20, 2013 at 12:46

xmonk

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