how to code with debug options in java

Question

I am trying to learn the trick on how to run the code which prints a lot of stuff when the debug flag is on.

How is that done in java.

A very naive way I can think of is have the debug flag in all the methods i write

and write something like

 if (this.debug == true){
 System.out.println("blah blah");
  }

But there should be much more elegant way rather than having all these ifs in code?

Also, is there a way I can get the line number of certain execution in code:

For example if there is an exception

            try:

/* line number 22 */

 catch Exception e{
         //print that exception occured in above line number??
    }

Probably very lame questions. THanks

Jigar Joshi · Accepted Answer · 2013-01-14 21:08:19Z

7

Use logging framework that will do it for you - for example : log4j, slf4j

For example:

log.debug("some text");

now in logging configuration properties file choose to enable disabled debug logging statements

See

answered Jan 14, 2013 at 21:08

Jigar Joshi

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erhun · Accepted Answer · 2013-01-14 21:18:46Z

2

Simple example from log4j API

private Logger _debugLogger = Logger.getLogger(yourClassName.class);
//For info mode
_debugLogger.info("Some Messages");
//or for debug mode
_debugLogger.debug(MessageFormat.format("Some message {0},{1},{2}",variable0, variable1,variable2));

answered Jan 14, 2013 at 21:18

erhun

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