Building a simple array

Question

I have an array that looks like this. Imagine there are 10 other keys like "Divertissement" in the principal array (this is only one branch of the principal array).

 array (size=8)
 'Divertissement' => 
    array (size=3)
  'Cosmic Top' => 
    array (size=3)
      'Cat' => string '7' (length=1)
      'Prix' => string '2.99' (length=4)
      'Desc' => string 'SOME TEXT'
  'Episodes' => 
    array (size=3)
      'Cat' => string '7' (length=1)
      'Prix' => string '3.99' (length=4)
      'Desc' => string 'SOME TEXT"
  'Rocket Deal' => 
    array (size=3)
      'Cat' => string '7' (length=1)
      'Prix' => string '0.99' (length=4)
      'Desc' => string SOME TEXT"

I am trying with no succes to create a new array that removes the first level array for each branch. So it would just remove "Divertissement", and start directty at Cosmic Top, Episodes, Rocket Deal as first level arrays.

moonwave99 · Accepted Answer · 2012-12-17 01:05:14Z

3

Just merge every top-level entry to a new array:

$newArray = array();

foreach($yourArray as $item)
{

    $newArray = array_merge($newArray, $item);

}

edited Dec 17, 2012 at 1:05

answered Dec 17, 2012 at 0:57

moonwave99

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5 Comments

Yanick Rochon Over a year ago

was about to suggest exactly that

user1834464 Over a year ago

I don't get it :(. Can you use the elements of my array so I can understand better?

moonwave99 Over a year ago

@Maxwell: sorry, I forgot to assign the merged value on each iteration, see my edit.

user1834464 Over a year ago

Nvm I got it! Thanks it works like a char, even though I don,t really get how it works lol.

user1834464 Over a year ago

Oh shit, I just got how it works, awesome function! Thanks again!

Petah · Accepted Answer · 2012-12-17 00:54:20Z

1

Just pop it off:

$array = array_pop($array);

answered Dec 17, 2012 at 0:54

Petah

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Comments

Carl Owens · Accepted Answer · 2012-12-17 01:10:33Z

0

You could assign the array key values to a new array:

$newArray = $currentArray['Divertissement'];

answered Dec 17, 2012 at 1:10

Carl Owens

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