how to remove the repeated value in an array and in between arrays using jQuery

Question

In my code I need to find the repeated value and give an alert using jQuery. Below is the example arrays and my requirement. Please help.

            a1 = {1,2,3,4,5,6,4}
            a2= {9,8,7},
            a3= {a,b,c,d,e,7}

In the above arrays I need to get the value 4 and give alert because it is repeating in array "a1" and I need to get the value 7 because it is repeating in the arrays 'a2' and 'a3'.
The first issue I fixed like as follows. Ineed to to fix the second one.

        for (var $i = 0; $i<= $last; $i++)
        {
        var hours = [];
        var minutes = [];
        var activeTime = [];    
        $.each($('.hour'+$i),function() {
       hours.push($(this).val());    
         });
       $.each($('.hour'+$i).next('select'),function(){
        minutes.push($(this).val());
       });
       for ( var i = 0; i < hours.length; i++ ) {
          activeTime.push(hours[ i ]+":"+minutes[ i ]+":"+"00");
         }
         for ( var i = 0; i <= hours.length; i++ ) {
          if ( hours[ i ] === "" )
           {
          $("#timeValidate"+$i).css("display", "block");
           return false;
           }
            else
             {
            $("#timeValidate"+$i).css("display", "none");
            }
            }
          for(var i=0; i< activeTime.length; i++)
          {
           for(var j = 0; j< activeTime.length; j++)
           {
          if( i != j)
             {
           if(activeTime[j] == activeTime[i])
              {
            $("#timeValidate"+$i).text("");
            $("#timeValidate"+$i).text("active time"+activeTime[j]+" is repeating");
             $("#timeValidate"+$i).css("display", "block");
            return false;
            }
            }
             }
            }
           }

Those don't look like arrays, in fact that's invalid syntax. — elclanrs
– elclanrs, Commented Nov 27, 2012 at 9:18
Hint: concat your arrays before checking for duplicates. That way you don't have to care about whether or not the duplicates are in different source arrays. — David Hedlund
– David Hedlund, Commented Nov 27, 2012 at 9:21

David Hedlund · Accepted Answer · 2012-11-27 09:37:56Z

1

function getDuplicatesFromArrays() {
    var allItems = Array.prototype.concat.apply([], arguments);
    var duplicates = [];
    var hash = {};

    allItems.forEach(function(x) {
        if(hash.hasOwnProperty(x)) duplicates.push(x);
        hash[x] = 1;
    });

    return duplicates;
}

The above function accepts any number of arrays, and yields the duplicates:

getDuplicatesFromArrays(a1,a2,a3) // [4, 7]

Demo

It works as sort of an inverse hash sieve; adding to duplicates only if the item was already in the hash.

answered Nov 27, 2012 at 9:37

David Hedlund

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2 Comments

Mansoor Over a year ago

How to call the function with 'n' number of array using a loop

David Hedlund Over a year ago

@Mansoor: the function accepts any number of arrays getDuplicatesFromArrays(a,b,c,d,e,f,g,h,i,j,k) would be fine, if those are all arrays.

Marius Stuparu · Accepted Answer · 2012-11-27 09:38:09Z

0

Try sugar.js, it has advanced functions for arrays (and others). For example, you can use a combination of unique() and subtract() to get an array that contains only the elements that are repeated. Then you can parse it and alert for each one.

answered Nov 27, 2012 at 9:38

Marius Stuparu

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Comments

score 0 · Accepted Answer · 2012-11-27 10:04:30Z

0

Here you go:

var original = [].concat(a,b,c),
    dupes = [];
for (var c = 0; c < original.length; c++) {
    if (original.filter(function(v) {
        return v == original[c];
    }).length > 1) {
        dupes.push(original[c]);
    }
}
alert($.grep(dupes, function(v, k){return $.inArray(v , dupes) === k;}));

Here is a demo: http://jsfiddle.net/q2c42/

edited Nov 27, 2012 at 10:04

answered Nov 27, 2012 at 9:36

user1726343

6 Comments

Mansoor Over a year ago

There will be n times of array then how we will try this

user1726343 Over a year ago

@Mansoor Updated and provided an example. Also alerts the dupes only once.

David Hedlund Over a year ago

This demo yields an empty array for me.

user1726343 Over a year ago

@DavidHedlund Gives me [4,7], although the previous version had this problem. Try refreshing the page and trying the demo (this one)

David Hedlund Over a year ago

@Asad: yes, your demo isn't updated so I used the code in your answer. It works, if I replace arr with original and dupes, respectively.

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