Function type using typescript

Question

Why do I have to cast function into Function type to be able to access apply and other members?

var a: Function = () => {};
a.apply(); // works

var a = () => {};
a.apply(); // does not work

How should I do it with these functions?:

function a(){}
a.apply(); // does not work

Fenton · Accepted Answer · 2012-11-17 20:45:04Z

1

If you pass the "this" argument to the apply function, it seems to work either way:

var a = () => {};
a.apply(null);

var b: Function = () => {};
b.apply(null);

answered Nov 17, 2012 at 20:45

Fenton

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2 Comments

Oldrich Svec Over a year ago

Interesting. It works but the intellisense for apply does not work. Do you observe the same and is it not a bug?

Fenton Over a year ago

I think this is deliberate. It doesn't suggest apply in the intellisense list, but if you type apply( it is aware of it and hints at the required arguments. I can't speak on behalf of the TypeScript team - but I think this could be deliberate. The same is true of call.

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