How do I run a script using another script in linux?

Question

My script is:

/opt/Myapplication/bin/start.sh

I always have to start it this way:

$cd /opt/Myapplication
$bin/start.sh

Now I want to write a script, which will run start.sh as above. I mean, it should run it from /opt/Myapplication directory

Maybe like this:

#!/bin/bash

my_path=/opt/Myapplication
$my_path/bin/start.sh

Will it run start.sh from /opt/Myapplication directory?

mata · Accepted Answer · 2012-11-16 19:00:07Z

1

it will run /opt/Myapplication/my_path/bin/start.sh, but it won't change the working directory, if that's what you mean. To do that, you'll have to cd in the script first:

#!/bin/bash

my_path=/opt/Myapplication
cd $my_path
$my_path/bin/start.sh

answered Nov 16, 2012 at 19:00

mata

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2 Comments

alwbtc Over a year ago

maybe ./bin/start.sh in last line?

mata Over a year ago

that doesn't really make any difference, it just uses the relative path instead of the absolute, the result is the same.

Tuim · Accepted Answer · 2012-11-16 19:01:29Z

0

You want to avoid scripts that need to be in a specific location to work properly

But no it will not run with that working directory, you have to cd first

#!/bin/bash
cd /opt/Myapplication/bin
bash start.sh

answered Nov 16, 2012 at 19:01

Tuim

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2 Comments

alwbtc Over a year ago

No, I must run it from /opt/Myapplication directory.

Andy Ross Over a year ago

Use a subshell if you want to avoid cwd pollution: (cd /opt/Myapplication && ./start.sh)

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