In a module, I have two functions, let's call them f and g. g takes a named argument f. I'd like to call f from inside g. How do I access the function f? Unfortunately, due to compatibility issues, I can't change their names.
Edit
To clarify, this is what I mean:
def f():
... code ...
def g(f=1):
... code ...
x = f() # error, f doesn't name the function anymore
... code ...
You could add a new name for the function.
E.g:
def f():
pass
f_alt = f
def g(f=3):
f_alt()
Just don't export f_alt from the module.
def g(f=3, f_alt=f).
g(4, 6) # fail hard. That is to say — this is not what function parameters are for, and it points out Python's need for a more flexible approach to variable scopes.def g(f=3, *, f_alt=f).Basic example using globals:
def f():
print 'f'
def g(name):
globals()[name]()
g('f')
Though globals() seems like a simple solution here, you can also achieve the same thing by defining a inner function inside g() that calls the global f:
def f():print "hello"
def g(f):
def call_global_f():
global f
f()
call_global_f() #calls the global f
print f #prints the local f
g('foo')
output:
hello
foo
