IN Node.js, with MongoDB, Mongoosejs as orm
I am doing this
I have a model, User
User.findOne({username:'someusername'}).exec(function(err,user){
console.log(user) //this gives full object with something like {_id:234234dfdfg,username:'someusername'}
//but
console.log(user._id) //give undefined.
})
Why? And how to get the _id to string then?
Try this:
user._id.toString()
A MongoDB ObjectId is a 12-byte UUID can be used as a HEX string representation with 24 chars in length. You need to convert it to string to show it in console using console.log.
So, you have to do this:
console.log(user._id.toString());
Take the underscore out and try again:
console.log(user.id)
Also, the value returned from id is already a string, as you can see here.
I'm using mongojs, and I have this example:
db.users.findOne({'_id': db.ObjectId(user_id) }, function(err, user) {
if(err == null && user != null){
user._id.toHexString(); // I convert the objectId Using toHexString function.
}
})
str property of ObjectId-type objects. It does, however, describe the ObjectId.toString() method, which as far as I can tell is the best answer.If you're using Mongoose, the only way to be sure to have the id as an hex String seems to be:
object._id ? object._id.toHexString():object.toHexString();
This is because object._id exists only if the object is populated, if not the object is an ObjectId
When using mongoose .
A representation of the _id is usually in the form (received client side)
{ _id: { _bsontype: 'ObjectID', id: <Buffer 5a f1 8f 4b c7 17 0e 76 9a c0 97 aa> },
As you can see there's a buffer in there. The easiest way to convert it is just doing <obj>.toString() or String(<obj>._id)
So for example
var mongoose = require('mongoose')
mongoose.connect("http://localhost/test")
var personSchema = new mongoose.Schema({ name: String })
var Person = mongoose.model("Person", personSchema)
var guy = new Person({ name: "someguy" })
Person.find().then((people) =>{
people.forEach(person => {
console.log(typeof person._id) //outputs object
typeof person._id == 'string'
? null
: sale._id = String(sale._id) // all _id s will be converted to strings
})
}).catch(err=>{ console.log("errored") })
[object Object]starting from Mongoose 5.4, you can convert ObjectId to String using SchemaType Getters.
see What's New in Mongoose 5.4: Global SchemaType Configuration.
function encodeToken(token){
//token must be a string .
token = typeof token == 'string' ? token : String(token)
}
User.findOne({name: 'elrrrrrrr'}, function(err, it) {
encodeToken(it._id)
})
In mongoose , the objectId is an object (console.log(typeof it._id)).
There are multiple approaches to achieve it ...
objectId.toString()
Using String Constructor
String(objectId)
Using Template Literals
const stringId = `${objectId}`;
Using Concatenation
const stringId = '' + objectId;
Using JSON.stringify
const stringId = JSON.stringify(objectId);
Access the property within the object id like that user._id.$oid.
Really simple use String(user._id.$oid)
try this : console.log(user._doc._id)
The result returned by find is an array.
Try this instead:
console.log(user[0]["_id"]);
find was used, but this is findOne.
find. Spent two hours trying to find this information. Thank you.
None of the above was working for me. I had to use
import { ObjectID } from 'bson';
(id as unknown as ObjectID).toString('hex');
In typescript
